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dezoksy [38]
3 years ago
9

Let z denote a random variable that has a standard normal distribution. Determine each of the probabilities below. (Round all an

swers to four decimal places.)P(z 2.37)
Mathematics
1 answer:
Lorico [155]3 years ago
4 0

Answer:

P(Z < 2.37) = 0.9911.

Step-by-step explanation:

We are given that Let z denote a random variable that has a standard normal distribution.

Let Z = a random variable

So, Z ~ Standard Normal(0, 1)

As we know that the standard normal distribution has a mean of 0 and variance equal to 1.

                          Z  =  \frac{X-\mu}{\sigma}  ~ N(0,1)

where, \mu = mean = 0

           \sigma = standard deviation = 1

Now, the probability that z has a value less than 2.37 is given by = P(Z < 2.37)

        P(Z < 2.37) = P(Z < \frac{2.37-0}{1} ) = P(Z < 2.37) = 0.9911

The above probability is calculated by looking at the value of x = 2.37 in the z table which has an area of 0.9911.

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Complete Question

The complete question is shown on the uploaded image  

Answer:

1 ) The correct option B

2) The correct option is  C

3)  The correct option is  C

4)  The correct option is  C

Step-by-step explanation:

From the question we are told that

   The proportion that own a cell phone  is  p = 0.90

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Generally the standard deviation of the number of students who own a cell phone in a simple random sample of 15 students is mathematically represented as

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Generally the probability that all students in a simple random sample of 15 students own a cell phone is mathematically represented as

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From the combination calculator  is      \left 15} \atop {}} \right.C_{15} =  1

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