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3 years ago

Two numbers are in the ratio of 3:4. If 9 is subtracted from their sum, the result is 40. What is the greater number?

Mathematics

1 answer:

nikklg [1K]3 years ago

6 0

Answer:

H.28

Step-by-step explanation:

x : y = 3 : 4

=> 4x=3y => x=3y/4 -----(1)

(x+y)-9=40

=>x+y=49

using (1)

3y/4 +y= 49

y=28

substituting y in (1)

x=21

hence 28 is greater.

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A group of retailers will buy 104 televisions from a wholesaler if the price is $300 and 144 if the price is $250. The wholesale

stepladder [879]

Answer:

The required equilibrium point is (356.538,58.769)

Step-by-step explanation:

The two points on your demand equation are : (300,104) and (250,144)

Take the number of televisions on y-axis and the price of the television on x-axis

Now, to find the demand equation for the given problem, find slope using the above two points :

$\implies Slope=\frac{144-104}{250-300}\\\\\implies Slope = -\frac{4}{5}=-0.8$

And the y - intercept is : y = -0.8x + b

Find the value of b using any point. Let us take (250,144)

144 = -0.8 × 250 + b

⇒ b = 144 + 200

⇒ b = 344

So, the y-intercept is : y = -0.8x + 344

The two points on your supply equation are : (225,88) and (315,68)

Take the number of televisions on y-axis and the price of the television on x-axis

Now, to find the supply equation for the given problem, find slope using the above two points :

$\implies Slope=\frac{68-88}{315-225}\\\\\implies Slope = -\frac{2}{9}$

And the y - intercept is :

$y = -\frac{2}{9}x + b$

Find the value of b using any point. Let us take (225,88)

$88 = -\frac{2}{9}\times 225 + b\\\\\implies b = 88 + 50\\\\\implies b = 138$

So, the y-intercept is :

$y = -\frac{2}{9}x + 138$

To find the equilibrium point, solve both the y-intercepts of the demand equation and the supply equation :

⇒ x = 356.538 and y = 58.769

Hence, the required equilibrium point is (356.538,58.769)

8 0

3 years ago

Indirect Proof help! WILL MEDAL

Charra [1.4K]

The area of the rectangle:
A = Length x Width = JK x KL = 36 cm²
If JK ≥ 4 cm, we have to prove that KL ≤ 9 cm.
Answer:
Assume that a. KL > 9 cm.
Then the area of rectangle JKLM is greater than b. 36 cm²,
which contradicts the given information that c. side is at least 4 cm long.
So the assumption must be false. Therefore, d. KL ≤ 9 cm.

4 0

4 years ago

Why are the solutions to the proportions 40/8 = x/10 and x/40 = 10/8 the same?

romanna [79]

Answer:

Both proportions are equivalent.

Step-by-step explanation:

We have been given two proportions $\frac{40}{8}=\frac{x}{10}$ and $\frac{x}{40}=\frac{10}{8}$ . We are asked to find why the solutions to our given proportions are equal.

We can solve proportions by cross multiplying them.

After cross multiplying our both proportions we will get same equation that is:

$40*10=8*x$

$400=8x$

$8*x=40*10$

$8x=400$

Since we get same equation after cross multiplying both proportions, therefore, the solutions to the given proportions would be same.

4 0

3 years ago

Read 2 more answers

Which equation has the same soultions as x^2+6×-7=0

blagie [28]

$x^2+6x-7=0 \\ a=1 \\ b= 6 \\ c=-7 \\ \\ \boxed{\boxed{\Delta=b^2-4ac}} \\ \\ \Delta=6^2-4*1*(-7) \\ \Delta=36-(-28) \\ \Delta=64 \\ \Delta\ \textgreater \ 0 \Rightarrow \text{we have 2 solutions :} X_1 \ and X_2 \\ \\ \boxed{X_1= \frac{-b- \sqrt{\Delta} }{2a} } \Rightarrow X_1= \frac{-6-8}{2}=-7 \\ \\ \boxed{X_2= \frac{-b+ \sqrt{\Delta} }{2a} } \Rightarrow X_2= \frac{-6+8}{2} =1$