All categories

3 years ago

Can you help with a math problem

Mathematics

1 answer:

qaws [65]3 years ago

5 0

I believe that they are both the first answer because when the sign has a line under it, it is darken in the circle

You might be interested in

If the equation of a circle is (x+5)^2 + (y-7)^2=36, its center point is

BigorU [14]

Answer:

centre = (- 5, 7 )

Step-by-step explanation:

The equation of a circle in standard form is

(x - h)² + (y - k)² = r²

where (h, k) are the coordinates of the centre and r is the radius

(x + 5)² + (y - 7)² = 36 ← is in standard form

with h = - 5 and k = 7

centre = (- 5, 7)

3 0

3 years ago

Write the slope-intercept form of the equation of the line through the given points:

vredina [299]

Answer:

equation of line

x-2y=8

Step-by-step explanation:

equation of line in slope intercept form

(y-y1)={(y2-y1)/(x2-x1)}(x-x1)

or,(y+3)={(-5+3)/(-2-2)}(x-2)

or,(y+3)=(1/2)(x-2)

or,2y+6=x-2

or,6+2 =x-2y

or,x-2y=8

3 0

3 years ago

Consider the function f(x) = 3x − 2. Select True or False for each statement. The y-intercept is 2. A True B False The x-interce

iragen [17]

Answer: A false, B true, C true

Step-by-step explanation:

A) intercept with y axis

That means x=0

y= 3*0-2

y= -2 So A is false

B) intercept with x axis

That means y=0

0= 3x-2

2=3x

2/3= x B is true

C) The form of linear function is

f(x)= mx +n, where m is the slope

In this case m= 3 so C is true

8 0

3 years ago

a scalene triangle has an area of 20.335 square centimeters. the height of the triangle is 8.3 centimeters. what is the length o

UNO [17]

Area of triangle = (1/2)*base*height

20.335 = (1/2)*base*8.3

2*20.335 = base*8.3

(2*20.335) / 8.3 = base Use your calculator.

4.9 = base

base = 4.9cm

5 0

3 years ago

How can i find The function of f(x) = 150 (1.3)^t

natka813 [3]

Answer:

See below.

Step-by-step explanation:

In comments, you said you wanted it graphed.

If it says f(x) on the left side, the equation should have an 'x' on the right side, so something is fishy here.

But, in an effort to try and help you ....

With the data you have given, I would graph it just like y = 150 (1.3)^x

You can pick various values for x, like -3,-2,-1,0,1,2,3 and see what y is for each one, then plot the points on graph paper.

If x = 0, y= 150(1.3)^0 = 150(1) = 150 because anything to power zero is 1

If x = -1, y= 150(1.3)^(-1) = 150(1/1.3) ≈ 132.7

If x = +1, y= 150(1.3)^(1) = 150(1.3) = 195

And so on.

I did the graph on DESMOS and it has a very large scale.

4 0

3 years ago