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krek1111 [17]
3 years ago
14

Write an equivalent expression for 8y + 12 + 2y + 8

Mathematics
1 answer:
Whitepunk [10]3 years ago
8 0
To solve this, combine like terms.

The terms are:
8y
12
2y
and 8

The like terms are:
8y and 2y
12 and 8

8y + 2y = 10y
12 + 8 = 20

Answer: 10y + 20
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Can someone solve 8 = b - 1 + 8b STEP BY STEP PLEASE
andrew11 [14]

Answer:

8 = b - 1 + 8b

group like terms

8 + 1 = b + 8b

9 = 9b cus b standing alone me 1b

divide both side by 9

<u>9</u><u> </u> = <u>9</u><u>b</u>

9 9

b = 1

7 0
3 years ago
Which system of linear inequalities is graphed?
ANEK [815]

To determine the system of inequality that has been graphed, we need to be very smart.


Observe that all the equations are the same.


Also note that all the lines are solid. This should tell you that the inequities should involve.


\ge \:or\: \le



Therefore the answer is between option A and B.



So we choose a point in the solution region to discriminate between A and B.


Let us choose the origin since that is easy to evaluate.


We substitute into option A to get.

y\le 3x-1\:and\: x+ 3y \ge 6




0\le 3(0)-1\:and\: 0+ 3(0) \ge 6




0\le -1\:and\: 0\ge 6


The above statements are false



We now substitute into option B



y\ge 3x-1\:and\: x+ 3y \le 6




0\ge 3(0)-1\:and\: 0+ 3(0) \le 6




0\ge-1\:and\: 0 \le 6


Both statements are true, therefore the correct answer is option B.




8 0
4 years ago
Please help!!!!!!!!!!
lapo4ka [179]

Answer: 18.7

Step-by-step explanation:

Find the lengths of AB, BC, and CA

AB = \sqrt{(4-(-1))^{2} + (-1-4)^{2} } = 5\sqrt{2} ≈ 7.1

BC = \sqrt{(0-(-1))^{2} + (-3-4)^{2} } = 5\sqrt{2} ≈ 7.1

CA = \sqrt{(0-4)^{2} + (-3-(-1))^{2} } = 2\sqrt{5} ≈ 4.5

7.1 + 7.1 + 4.5 = 18.7

6 0
2 years ago
A.<br> If the side ratio is 5:13, then the area ratio is ?
frez [133]

25:169 can be if is a rectangle  ( times by the number itself )

or is is a square times by 2 ( 10/26)

8 0
3 years ago
Could someone answer all 5 questions please
xeze [42]

Answer:

3=111

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
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