Answer:
Let X the random variable that represent the number of emails from students the day before the midterm exam. For this case the best distribution for the random variable X is
The probability mass function for the random variable is given by:

The best answer for this case would be:
C. Poisson distribution
Step-by-step explanation:
Let X the random variable that represent the number of emails from students the day before the midterm exam. For this case the best distribution for the random variable X is
The probability mass function for the random variable is given by:
And f(x)=0 for other case.
For this distribution the expected value is the same parameter
And for this case we want to calculate this probability:

The best answer for this case would be:
C. Poisson distribution
Answer:
the 1st one
Step-by-step explanation:
It is an 8/15 probability. there are 15 marbles total (5y+7p+3pl=15)
5/15y, 7/15p, 3/15.
5/15+3/15= 8/15
Step-by-step explanation:
Line segment = EG
point on a line segment = F
EG = 100
EF = 4x - 20
FG = 2x + 30
a/q, EF + FG = EG
the equation is
4x - 20 + 2x + 30 = 100
now solution for x is
→ 4x - 20 + 2x + 30 = 100
→ 6x + 10 = 100
→ 6x = 100 - 10 = 90
→ x = 90/6 = 15
therefore, value of x is 15.
and according to given information
EF = 4x - 20 = 4(15) - 20 = 60 - 20 = 40
FG = 2x + 30 = 2(15) + 30 = 30 + 30 = 60
hope this answer helps you dear..take care and may u have a great day ahead!