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abruzzese [7]
3 years ago
15

You are considering building a residential wind power system to produce 6,000 kWh of electricity each year. The installed cost o

f the system is $1.50/Winstalled. The system is estimated to have a capacity factor of 22% and a 10 year life. The interest rate is 8% with an operations and maintenance cost of $0.04/kWhgenerated. What is the leveled cost of electricity for the system ($/kWh)?
Engineering
1 answer:
alisha [4.7K]3 years ago
8 0

Answer:

leveled cost of electricity LCOE is 0.1159/kwh

Explanation:

given data:

installation cost of system = $1.50/winstalled

capacity factor = 22%

life = 10 year

rate of interest 8%

operation and maintenance cost = $0.04 / kwh generated

capcaitence recovery factorCRF = \frac{i(i+1)^n}{(i+1)^n -1}

i= rate of interest

n = annuity period

CRF = \frac{0.08(1+0.08)^10}}{(1+0.08)^{10} -1} = 0.14903

LCOE = \frac{cost\ of \installation \times CRF}{hours/ available \times capacity\ factor} + variable\ o&M\ cost

=  \frac{1.50\times 1000/kw \times 0.14903}{8760\times 0.22} + 0.04/kwh

          = 0.1159/kwh + 0.04 /kwh

          = 0.1559 /kwh

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wariber [46]

Answer:

1) q=18414.93 W

2) C=12920$

Explanation:

Given data:

pipe length L=25m

pipe diameter D=100mm =0.1 m

air temperature T_{s1}=T_{\infty1} }=25 °C.....= 298.15k

pipe surface temp T_{s2}=150 °C.....=423.15k

surface emissivity e= 0.8

boiler efficiency η=0.90

natural gas price Cg=$0.02 per MJ

1) Total heat loss and radiation heat loss combined

          q=q_{conv} +q_{rad}

          q=A[h(T_{s2}-T_{s1})+eб(T_{s2}^4-T_{s1}^4)]....... (1)

б=5.67×10^-8 W/m^2K^4 (boltzmann constant)

area A =L.Dπ=25×0.1π=7.85 m^2

putting all these values in eq (1)

q=18414.93 W

2) suppose boiler is operating non stop annual energy loss will be

               E=q.t

                  =18414.93.3600.24.365

                  =5.81×10^11 J

   to find furnace energy consumption

               Ef =E/η

                  =6.46×10^5 MJ

   annual cost

                  C=Cg. Ef

                    =12920$

8 0
3 years ago
By the mid-1980s, the prices of economy cars had risen substantially, with the smaller Japanese and American sedans costing five
mash [69]

Answer:

Cause and effect

Explanation:

In this text, the most suitable structure is a cause and effect structure. The text explains why the prices of economy cars rose substantially in the United States during the mid-1980s. The initial cause was import quotas, which led to the effect of the Japanese sending mostly luxury cars to America. This pattern is reproduced through the passage, allowing us to understand the connection between different sentences within a paragraph.

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3 years ago
6. Driving with parking lights only (in place of headlights) is against the law. A. True B. False
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Answer:

B false it is illegal to only have got fog lights on though and bright headlights because it can distract other drivers going last and if the y are distracted then that will cause a collision

Hope this helps :)

Explanation:

4 0
3 years ago
Read 2 more answers
One kilogram of water fills a 0.140 m^3 rigid container at an initial pressure of 1.8 MPa. The container is then cooled to 40°C.
Pavel [41]

Answer:

T1 = 299.18 °C

P2 = 0.00738443 MPa

Explanation:

From the data, we can get two properties for the initial condition. These are pressure and specific volume.

The pressure is 1.8 MPa and the specific volume, we can get it with the mass and volume of the container, since it’s filled this is also the volume of the water in it.

v=\frac{vol (m^{3})}{mass (kg)} = \frac{0.140 m^{3}}{1 kg} = 0.140 \frac{ m^{3}}{kg}

When we check in the thermodynamic tables, the conditions for saturation at 1.8 MPa we found the following:

P^{sat} = 1.8 MPa

T^{sat} = 207.12 C

v_{g} = 0.1103\frac {m^{3}}{kg} specific volume for the saturated vapor  

v_{l} = 0.001167 \frac{m^{3}}{kg} specific volume for the saturated liquid  

Since the specific volume in our condition is higher that the specific volume for the saturated vapor, we have a superheated steam.  

Looking in the thermodynamic tables for superheated steam we found that the temperature where the steam has a specific volume of 0.140 \frac{ m^{3}}{kg} at 1.8 MPa is 299.18 °C. This is the initial temperature in the container.

Since the only information that we have about the final condition is that the container was cooled. We can assume that it was cooled until a condition of saturation. So, the final pressure for the water will be the pressure of saturation for a temperature of 40°C. From thermodynamic tables we get:

P^{sat} at 40C = 0.00738443 MPa

7 0
3 years ago
Design a sequential circuit DETECTOR that has one input X and one input Y. The DETECTOR detects the sequence 110. If an input X
Novosadov [1.4K]

Answer:

See explaination

Explanation:

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