Answer:
Rated power = 1345.66 W/m²
Mechanical power developed = 3169035.1875 W
Explanation:
Wind speed, V = 13 m/s
Coefficient of performance of turbine,
= 0.3
Rotor diameter, d = 100 m
or
Radius = 50 m
Air density, ρ = 1.225 kg/m³
Now,
Rated power = ![\frac{1}{2}\rho V^3](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%5Crho%20V%5E3)
or
Rated power = ![\frac{1}{2}\times1.225\times13^3](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%5Ctimes1.225%5Ctimes13%5E3)
or
Rated power = 1345.66 W/m²
b) Mechanical power developed = ![\frac{1}{2}\rho AV^3C_p](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%5Crho%20AV%5E3C_p)
Here, A is the area of the rotor
or
A = π × 50²
thus,
Mechanical power developed = ![\frac{1}{2}\times1.225\times\pi\times50^2\times13^3\times0.3](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%5Ctimes1.225%5Ctimes%5Cpi%5Ctimes50%5E2%5Ctimes13%5E3%5Ctimes0.3)
or
Mechanical power developed = 3169035.1875 W
Answer:
A renewable electricity generation technology harnesses a naturally existing energy. But they have other features that a few fringe customers value.
Explanation:
Answer:
design angle ∅ = 4.9968 ≈ 5⁰
Explanation:
First calculate the force Fac :
Fac = ![\sqrt{400^2 + 650^2 - 2(400)(650)cos30}](https://tex.z-dn.net/?f=%5Csqrt%7B400%5E2%20%2B%20650%5E2%20-%202%28400%29%28650%29cos30%7D)
= ![\sqrt{160000 + 422500 - 80210}](https://tex.z-dn.net/?f=%5Csqrt%7B160000%20%2B%20422500%20-%2080210%7D)
= 708.72 Ib
using the sine law to determine the design angle
![\frac{sin}{400} = \frac{sin 30}{Fac}](https://tex.z-dn.net/?f=%5Cfrac%7Bsin%7D%7B400%7D%20%20%3D%20%5Cfrac%7Bsin%2030%7D%7BFac%7D)
hence ∅ = ![sin^{-1} (\frac{sin 30 *400}{708.72} )](https://tex.z-dn.net/?f=sin%5E%7B-1%7D%20%28%5Cfrac%7Bsin%2030%20%2A400%7D%7B708.72%7D%20%29)
=
= 4.9968 ≈ 5⁰
Answer:
2543 k
Explanation:
This problem can be resolved by applying the first law of thermodynamics
<u>Determine the adiabatic flame temperature</u> when the furnace is operating at a mass air-fuel ratio of 16 for air preheated to 600 K
attached below is a detailed solution
cp = 1200
Answer:
COP(heat pump) = 2.66
COP(Theoretical maximum) = 14.65
Explanation:
Given:
Q(h) = 200 KW
W = 75 KW
Temperature (T1) = 293 K
Temperature (T2) = 273 K
Find:
COP(heat pump)
COP(Theoretical maximum)
Computation:
COP(heat pump) = Q(h) / W
COP(heat pump) = 200 / 75
COP(heat pump) = 2.66
COP(Theoretical maximum) = T1 / (T1 - T2)
COP(Theoretical maximum) = 293 / (293 - 273)
COP(Theoretical maximum) = 293 / 20
COP(Theoretical maximum) = 14.65