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Trava [24]
3 years ago
9

Solve. −1.2z−8.2>−9.7

Mathematics
2 answers:
dezoksy [38]3 years ago
7 0
<h2>Answer:</h2>

<u>The solution is</u><u> z < 1.25 </u>

<h2>Step-by-step explanation:</h2>

See the attached image for solution

Nikitich [7]3 years ago
5 0

Answer: z

Step-by-step explanation:

To solve this problem you must apply the proccedure shown below:

Add 8.2 to both sides of the inequality. Then, you obtain:

-1.2z-8.2+8.2>-9.7+8.2\\-1.2z>-1.5

Now you must divide both sides by -1.2, as you can see below:

\frac{-1.2z}{-1.2}>\frac{-1.5}{-1.2}

(The direction of the sign will change).

Therefore, you obtain the following solution:

z

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Suppose a tank contains 400 gallons of salt water. If pure water flows into the tank at the rate of 7 gallons per minute and the
Strike441 [17]

Answer:

Step-by-step explanation:

This is a differential equation problem most easily solved with an exponential decay equation of the form

y=Ce^{kt}. We know that the initial amount of salt in the tank is 28 pounds, so

C = 28. Now we just need to find k.

The concentration of salt changes as the pure water flows in and the salt water flows out. So the change in concentration, where y is the concentration of salt in the tank, is \frac{dy}{dt}. Thus, the change in the concentration of salt is found in

\frac{dy}{dt}= inflow of salt - outflow of salt

Pure water, what is flowing into the tank, has no salt in it at all; and since we don't know how much salt is leaving (our unknown, basically), the outflow at 3 gal/min is 3 times the amount of salt leaving out of the 400 gallons of salt water at time t:

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Therefore,

\frac{dy}{dt}=0-3(\frac{y}{400}) or just

\frac{dy}{dt}=-\frac{3y}{400} and in terms of time,

-\frac{3t}{400}

Thus, our equation is

y=28e^{-\frac{3t}{400} and filling in 16 for the number of minutes in t:

y = 24.834 pounds of salt

6 0
3 years ago
How do I find the range of a function (no links)
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Feliz is looking at a cyclic quadrilateral EFGH. He says, "I'm not convinced that opposite
attashe74 [19]

If the angle G is moved to a different spot in the circle the angle FGH and angle FEH in the cyclic quadrilateral will change to make it supplementary.

<h3 /><h3>What is a cyclic quadrilateral?</h3>

A cyclic quadrilateral is quadrilateral inscribed in a circle. It has all its vertices on the circumference of the circle.

Opposite angles in a cyclic quadrilateral are supplementary angles. That means they add up to 180 degrees.

Therefore, if he adjust point G to a different spot on the circle, angle FGH and FEH will adjust to become supplementary.

learn more on cyclic quadrilateral here: brainly.com/question/27884509

#SPJ1

8 0
1 year ago
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IMPORTANT PLEASE HELP!!
Oduvanchick [21]
I will think that the answer is d
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