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2 years ago

14

How do I find the range of a function (no links)

1 answer:

Anna11 [10]2 years ago

6 0

D is your answer because the bar is 4 and you must have an equal amount of plates on each side so it cannot be B. It goes up by 40 because of 2 plates on each side of the bar

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The table below shows the distance d(t) in meters that an object travels in t seconds:

ArbitrLikvidat [17]

(2,60)(4,240)......t = x and d(t) = y
average rate of change (slope) is (y2 - y1) / (x2 - x1)
slope = (240 - 60) / (4 - 2) = 180/2 = 90 m/s

It represents the average distance traveled by the object between 2 seconds and 4 seconds

5 0

3 years ago

PLS HELP 100 POINTS

DaniilM [7]

39

beacause this is the answer when you aolve it

4 0

3 years ago

Twenty percent of drivers driving between 10 pm and 3 am are drunken drivers. In a random sample of 12 drivers driving between 1

Lesechka [4]

Answer:

(a) 0.28347

(b) 0.36909

(c) 0.0039

(d) 0.9806

Step-by-step explanation:

Given information:

n=12

p = 20% = 0.2

q = 1-p = 1-0.2 = 0.8

Binomial formula:

$P(x=r)=^nC_rp^rq^{n-r}$

(a) Exactly two will be drunken drivers.

$P(x=2)=^{12}C_{2}(0.2)^{2}(0.8)^{12-2}$

$P(x=2)=66(0.2)^{2}(0.8)^{10}$

$P(x=2)=\approx 0.28347$

Therefore, the probability that exactly two will be drunken drivers is 0.28347.

(b)Three or four will be drunken drivers.

$P(x=3\text{ or }x=4)=P(x=3)\cup P(x=4)$

$P(x=3\text{ or }x=4)=P(x=3)+P(x=4)$

Using binomial we get

$P(x=3\text{ or }x=4)=^{12}C_{3}(0.2)^{3}(0.8)^{12-3}+^{12}C_{4}(0.2)^{4}(0.8)^{12-4}$

$P(x=3\text{ or }x=4)=0.236223+0.132876$

$P(x=3\text{ or }x=4)\approx 0.369099$

Therefore, the probability that three or four will be drunken drivers is 0.3691.

(c)

At least 7 will be drunken drivers.

$P(x\geq 7)=1-P(x$

$P(x\leq 7)=1-[P(x=0)+P(x=1)+P(x=2)+P(x=3)+P(x=4)+P(x=5)+P(x=6)]$

$P(x\leq 7)=1-[0.06872+0.20616+0.28347+0.23622+0.13288+0.05315+0.0155]$

$P(x\leq 7)=1-[0.9961]$

$P(x\leq 7)=0.0039$

Therefore, the probability of at least 7 will be drunken drivers is 0.0039.

(d) At most 5 will be drunken drivers.

$P(x\leq 5)=P(x=0)+P(x=1)+P(x=2)+P(x=3)+P(x=4)+P(x=5)$

$P(x\leq 5)=0.06872+0.20616+0.28347+0.23622+0.13288+0.05315$

$P(x\leq 5)=0.9806$

Therefore, the probability of at most 5 will be drunken drivers is 0.9806.

5 0

3 years ago

Given: 5n-42=12n prove: n=-6

Vikentia [17]

Answer:

n=-6

Step-by-step explanation:

5n-42=12n

5n=12n+24

5n-12n=42

-7n=42

divide each side by -7

n does =-6

3 0

3 years ago

Read 2 more answers

Mr grain left for work at 7:15 am. twenty five mintutes later he aririved at his work. what time did mr giarmo arrive at his

Genrish500 [490]

25 minutes (0:25) added to 7:15.

7:15 + 0:25 = 7:40
Also expressible as 15+25

He arrived at 7:40AM.

5 0

2 years ago