Sorry, don't have time to do them right now but I know who does!
http://www.wolframalpha.com/widgets/view.jsp?id=ae438682ce61743f90d4693c497621b7
Just plug in 2 at a time.
Answer:
The first step that we are going to do is to solve the area of the top rectangle. We are given a width of 15 cm and a length of 25 cm so we can just multiply them against each other to get the area.



The second side that we are going to solve for is the bottom rectangle. We are given a width of 12 cm and a length of 25 cm so lets just multiply them against each other to get the area.



The next area that we are going to determine is the back rectangle which has a width of 9 cm and a length of 25 cm so lets just multiply them against each other to get the area.



The final area that we have to determine are the side triangles. After determining the area of one triangle we will have to multiply it by 2 to get the area for both of the triangles. We are given a base of 12 cm and a height of 9 cm so lets just use the formula to find the area.



Multiply it by two to get the area for both of the triangles.


Finally, we are onto the last part which is to add up all of the areas and get the surface area after we combine everything.


Therefore, our final answer is option B, 1008 
Hope this helps!
To find the average velocity in a velocity-time graph at a particular interval, simply determine the gradient at that particular interval.
<span>a. average velocity= 4/1 </span>
<span>= 4m/s </span>
<span>b. average velocity from 1 to 2.5s= 6/(2.5-1) </span>
<span>= 4m/s </span>
<span>average velocity from 2.5 to 4.0s= 0m/s </span>
<span>average velocity from 0 to 4.0s= (4+0)/4 </span>
<span>= 1m/s </span>
<span>c. average velocity from 1.0 to 4.0s= (4/3)m/s </span>
<span>average velocity from 4.0 to 5.0s= 2/1 </span>
<span>= 2.0m/s </span>
<span>average velocity from 1.0 to 5.0s= ((4/3)+2)/4 </span>
<span>= (5/6)m/s </span>
<span>d. average velocity from 0 to 4.0s= 1.0m/s </span>
<span>average velocity from 4.0 to 5.0s= 2.0m/s </span>
<span>average velocity from 0 to 5.0s= (1.0+2.0)/5 </span>
<span>= (3/5)m/s </span>
Answer:
1,318
Step-by-step explanation:
you will multiple 6.59 by 2