Answer:
The temperature of the beaker with water should change very little compared with the beaker with just air, demonstrating that the heat capacity of water can resist changes in air temperature.
As Joe first focuses his attention and his eyes on the tree, he needs to know that the focal length of the cornea lens system in his eyes must be less than the distance between the front and the back of his eye.
Answer: A plant cell has a cell wall, a central vacuole, and phosphids or chloroplasts. The cell wall provides structural support and protection.
Assuming Hardy-Weinberg equilbrium, we have
p + q = 1
where p = frequency of dominant allele and q = frequency of recessive allele. So
p = 1 - q = 1 - 0.04 = 0.96
Consequently we have
• p² = 0.9216 = frequency of hom ozygous domininant genotype
• pq = 0.0768 = frequency of heterozygous genotype
• q² = 0.0016 = frequency of hom ozygous recessive genotype
since
p² + 2pq + q² = 1
<span>If the black horse is homozygous, what is its genotype?
BB
If the black horse is heterozygous, what is its genotype?
Bb
Hope this helps!
-Payshence xoxo</span>
