Opposite of 12? it must be 21 then
sum = 14 + 21 = 35
If 'a' is a rational number and c is rational, then
a = p/q
c = r/s
where p,q,r,s are integers (q and s can't be zero)
Subtracting c-a gives
b = c-a
b = (p/q) - (r/s)
b = (ps/qs) - (qr/qs)
b = (ps - qr)/(qs)
The quantity pq - qr is an integer. The reason why is because ps and qr are both integers (multiplying any two integers leads to another integer). Subtracting any two integers results in another integer.
So we have (ps - qr)/(qs) in the form (integer)/(integer) = rational number
Therefore, b is a rational number, but this contradicts the given info that b is irrational. If b is irrational, then we CANNOT write it as a ratio of integers.
This contradiction proves the assumption "a+b = c and c is rational" is incorrect
The sum is irrational.
Therefore, if a+b = c, where 'a' is rational and b is irrational, then c is irrational.
Answer:
TS = 6.6 (nearest tenth)
Step-by-step explanation:
<u>Secant</u>: a straight line that intersects a circle at two points.
<u>Tangent</u>: a straight line that touches a circle at only one point.
<u>Theorem</u>
When a secant segment and a tangent segment meet at an exterior point, the square of the measure of the tangent segment is equal to the product of the measures of the secant segment and its external secant segment.
Given:
- Tangent segment = QR
- Secant segment = TR
- External secant segment = SR
⇒ QR² = TR · SR
⇒ 19² = (TS + 16) · 16
⇒ 361 = (TS + 16) · 16
⇒ 22.5625 = TS + 16
⇒ TS = 22.5625 - 16
⇒ TS = 6.5625
⇒ TS = 6.6 (nearest tenth)
Answer:
s = d/t and d = s × t
Step-by-step explanation:
s = d/t
d = s × t