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pogonyaev
3 years ago
8

Zohar is using scissors to cut a rectangle with a length of 5x – 2 and a width of 3x + 1 out of a larger piece of paper. Which e

xpression can be used to find the perimeter of the rectangle and what is the perimeter if x = 4?
Mathematics
2 answers:
sweet-ann [11.9K]3 years ago
4 0

Answer with Step-by-step explanation:

Zohar cut a rectangle with a length of 5x – 2

and a width of 3x + 1

We know that:

Perimeter of rectangle is:

Perimeter=2(length+width)

                =2(5x-2+3x+1)

                =2(8x-1)

                =16x-2

Hence, expression which can be used to find the perimeter of the rectangle is:

16x-2

Now, when x=4

16x-2=16×4-2

        =62

Hence, when x=4 ,Perimeter=62

Andreyy893 years ago
4 0

Answer:

P=2(8x-1)

P=62 at x=4

Step-by-step explanation:

Given: The length of the rectangle is 5x-2 and width of the rectangle is 3x+1

To find: An expression that can be used to find the perimeter of the rectangle, and the perimeter when x is 4.

Solution:

Here, Length is given as 5x-2

width of the rectangle is 3x+1

Let P represents the perimeter of the rectangle

We know that perimeter of a rectangle is 2(l+w)

So, we have

P=2(l+w)

P=2(5x-2+3x+1)

P=2(8x-1)

Therefore, the expression to find the perimeter is P=2(8x-1)

Now, we need to find the perimeter at x=4

On substituting x=4  in P=2(8x-1) we have,

P=2(8(4)-1)

P=2(32-1)

P=2(31)

P=62

Hence, the perimeter is 62 units when x is 4.

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Read 2 more answers
Clovis is standing at the edge of a cliff, which slopes 4 feet downward from him for every 1 horizontal foot. He launches a smal
zmey [24]

Answer:

a) -2x^2 + 164x

b) 3362 feet

c) (82 , -328)

d) yes

Step-by-step explanation:

y = -2x^2 + 160x

Slope = 4 feet downward for every 1 horizontal foot.

a) h(x) = -2x^2 + 160x - (-4x)

= -2x^2 + 160x + 4x

= -2x^2 + 164x

b) The highest point occurs at the vertex of the parabolic equation. x is the same as the number of the axis of symmetry.

x = -b/2a

From the equation, a = -2 , b= 164

x = -164/ 2(-2)

x = -164/-4

x = 41

Put x = 41 into the value of h(x)

h(x) = -2x^2 + 164x

= -2(41^2) + 164(41)

= -2(1681) + 6724

= -3362 + 6724

= 3362 feet.

The maximum height occurs at 41 feet out from the top of the sloping ground at a height of 3362ft about the top edge of the cliff.

c) h(x) = -2x^2 + 164x

2x^2 - 164x + h = 0 when 0 ≤ x ≤ 41

Solve the equation using the formula (-b+/-√b^2 - 4ac) / 2a

a = 2, b= -164 , c = h

= [-(-164) +/- √(-164)^2 - 4(2)(h) ] / 2(2)

= (164 +/- √26896 - 8h)/ 4

This gives the value of -328 ≤ h ≤ 3362 is used because the rocket hits the sloping ground of (82 , -328)

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