Answer:
at ![x=4](https://tex.z-dn.net/?f=x%3D4)
Step-by-step explanation:
Given: The length of the rectangle is
and width of the rectangle is ![3x+1](https://tex.z-dn.net/?f=3x%2B1)
To find: An expression that can be used to find the perimeter of the rectangle, and the perimeter when x is 4.
Solution:
Here, Length is given as
width of the rectangle is ![3x+1](https://tex.z-dn.net/?f=3x%2B1)
Let P represents the perimeter of the rectangle
We know that perimeter of a rectangle is ![2(l+w)](https://tex.z-dn.net/?f=2%28l%2Bw%29)
So, we have
![P=2(l+w)](https://tex.z-dn.net/?f=P%3D2%28l%2Bw%29)
![P=2(5x-2+3x+1)](https://tex.z-dn.net/?f=P%3D2%285x-2%2B3x%2B1%29)
![P=2(8x-1)](https://tex.z-dn.net/?f=P%3D2%288x-1%29)
Therefore, the expression to find the perimeter is ![P=2(8x-1)](https://tex.z-dn.net/?f=P%3D2%288x-1%29)
Now, we need to find the perimeter at
On substituting
in
we have,
![P=2(8(4)-1)](https://tex.z-dn.net/?f=P%3D2%288%284%29-1%29)
![P=2(32-1)](https://tex.z-dn.net/?f=P%3D2%2832-1%29)
![P=2(31)](https://tex.z-dn.net/?f=P%3D2%2831%29)
![P=62](https://tex.z-dn.net/?f=P%3D62)
Hence, the perimeter is 62 units when x is 4.