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saveliy_v [14]
3 years ago
12

A sample of water is being heated over a flame. What happens to the water as it is heated? (2 points)

Chemistry
2 answers:
Viefleur [7K]3 years ago
6 0
The answer is D, the kinetic energy of the water molecules begins to increase. When you heat up a pot of water, the water molecules begin to move very fast. Thus, stating that the kinetic energy of water molecules increase since the water molecules go from moving a little bit to moving really fast! I hope this could help!
alexandr402 [8]3 years ago
4 0

Answer:   The kinetic energy of the water molecules increases.

Explanation:  When a sample of water is being heated over the flame, the kinetic energy of the molecules of the water increases.

As we know that, according to the kinetic theory of molecular gases, temperature is directly proportional to the velocity of the molecule.

Thus, when the water sample in the container is heated, the particles present at the bottom will see an increment in their velocity thus they will move upward and will try to escape the conatiner in the form of the vapors.

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How can you experimentally determine the pka of acetic acid?
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Explanation:

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HA(aq) + OH-(aq) --> H3O+(aq) + A−(aq)

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SSA PRACTICE QUESTION
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The correct answer is - so that other scientists can replicate the experiment and make sure the results are correct or to check accuracy.

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Complete combustion of 8.60 g of a hydrocarbon produced 26.5 g of CO2 and 12.2 g of H2O. What is the empirical formula for the h
amid [387]

The empirical formula of the hydrocarbon is C_2H_3 if combustion of 8.60 g of a hydrocarbon produced 26.5 g of CO_2 and 12.2 g of H_2O.

<h3>What is an empirical formula?</h3>

A chemical formula showing the simplest ratio of elements in a compound rather than the total number of atoms in the molecule CH_2O is the empirical formula for glucose.

1 mole of carbon dioxide contains a mass of 44 g, out of which 12 g are carbon.

Hence, in this case the mass of carbon in 8.46 g of CO_2:

(\frac{12}{44}) × 8.46 = 2.3073 g

1 mole of water contains 18 g, out of which 2 g is hydrogen;

Therefore, 2.6 g of water contains;

(\frac{2}{18} × 2.6 = 0.2889 g of hydrogen.

Therefore, with the amount of carbon and hydrogen from the hydrocarbon, we can calculate the empirical formula.

We first calculate the number of moles of each,

Carbon = \frac{2.3073}{12}  = 0.1923 moles

Hydrogen = \frac{0.2889}{1}= 0.2889 moles

Then, we calculate the ratio of Carbon to hydrogen by dividing by the smallest number value;

            Carbon : Hydrogen

               \frac{0.1923}{0.1923} : \frac{0.2889}{0.1923}

                      1 :  1.5

                     (1 : 1.5) 2

                    = 2 : 3

Hence, the empirical formula of the hydrocarbon is C_2H_3.

Learn  more about the empirical formula here:

brainly.com/question/14044066

#SPJ1

8 0
2 years ago
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