Borane (BH3) adds to alkenes to form an alkylborane. In the first box draw the mechanism arrows, and in the second box draw the
correct product. Be sure to add lone pairs of electrons and nonzero formal charges to all species.
1 answer:
Answer:
The reaction when the Borane (BH3) is add to an alkene and form an alkylborane is shown below.
Explanation:
The boron of the borane does not have extra electron pairs, in this way the double bond of the alkene attacks the boron and the hydrogen belonging to the borane adheres to the carbon that is more substituted, thus forming an alkyl borane.
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Answer:
3.72L
Explanation:
Given parameters:
Initial volume V₁ = 3.9L
Condition = STP
Final temperature T₂ = -550°C
Final pressure P₂ = 880mmHg
Unknown:
Final volume V₂ = ?
Solution.
At standard temperature and pressure(STP), the:
Pressure = 1atm = 760mmHg
Temperature = 273K
Therefore, P₁ = 760mmHg
T₁ = 273K
The general gas law, is best to solve this problem. It is mathematically given as:
Let us take the units to the appropriate one;
-550°C = 273 + (-550) = -277K
Input the variables;
V₂ = 3.72L