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3 years ago

What is true about all matter?

Chemistry

1 answer:

Ipatiy [6.2K]3 years ago

8 0

Alll are correct. Matter is literally everywhere

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Elements on the periodic table are arranged by increasing ?

Galina-37 [17]

They are arranged by their atomic mass.

5 0

3 years ago

Name at least three types associated with the microwave

Bond [772]

Hi , if you are asking for the types of energy , here's your answer:

1. Radiative energy , because the microwave is releasing radiation.
2.Light energy , because there is light inside the microwave.
3.electronic energy , because the microwave is using electricity.

8 0

3 years ago

Helium gas in a cylinder is under 1.12atm pressure at 25.0C. What will be the pressure if the temperature increases to 37.0C?

Irina18 [472]

Answer:

$p_2=1.17atm$

Explanation:

Hello!

In this case, considering that the Gay-Lussac's law allows us to relate the temperature-pressure problems as directly proportional relationships:

$\frac{p_2}{T_2} =\frac{p_1}{T_1} \\\\$

Thus, for the initial pressure and temperature in kelvins the final temperature in kelvins, we compute the final pressure as:

$p_2=\frac{p_1T_2}{T_1} \\\\p_2=\frac{1.12atm*310.15K}{298.15K}\\\\p_2=1.17atm$

Best regards!

7 0

2 years ago

Which element is reduced in this reaction? 2kmno4 3na2so3 h2o→2mno2 3na2so4 2koh

erik [133]

In a redox chemical reaction, one species gets reduced and another gets oxidized. Manganese element is reduced in this reaction.

<h3>What is oxidized and reduced?</h3>

In a redox reaction, the increase or decrease in the oxidation number and electrons results in the reduction and oxidation of the chemical species. The oxidation and reduction occur simultaneously in a reaction.

The oxidation number of Mn in permanganate ion was +8 on the left side and decreased to +4 on the right side of the equation. Potassium permanganate is an oxidizing agent that has reduced the manganese ion of the permanganate ion.

Therefore, manganese is reduced.

Learn more about reduction and oxidation here:

brainly.com/question/2427143

#SPJ4

3 0

2 years ago

Solid aluminum and gaseous oxygen read in a combination reaction to produce aluminum oxide. 4Al(s) + 3O_2(g) rightarrow 2Al_2O_3

Kryger [21]

Answer:

4.7 g. Option 5 is the right one.

Explanation:

4Al(s) + 3O₂ (g) ⇄ 2Al₂O₃ (s)

We convert the mass of reactants to moles, in order to determine the limiting.

2.5 g Al / 26.98 g/mol → 0.092 moles of Al

2.5 g O₂ / 32g/mol → 0.078 moles of O₂

Ratio is 4:3. 4 moles of Al react with 3 moles of O₂

Then, 0.092 moles of O₂ would react with (0.092 . 3)/ 4 = 0.069 moles O₂

We have 0.078 moles of O₂ and we need 0.069 moles, the oxygen is the limiting in excess. Therefore the Al is the limiting reactant.

Ratio is 4:2. 4 moles of Al, can produce 2 moles of Al₂O₃

Then, 0.092 moles of Al would produce (0.092 .2) / 4 = 0.046 moles

If we convert the moles to mass, we find the anwer:

0.046 mol . 101.96 g/mol = 4.69 g

5 0

3 years ago