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liberstina [14]
3 years ago
6

What is the mass (in mg) of 2.63 moles of nickel?

Chemistry
1 answer:
zaharov [31]3 years ago
8 0
Data:
Molar Mass of Nickel = 58,7 g/mol

Solving:
58,7 g → 1 mol
y -------→ 2.63 mol

Solving: (They are proportional measures, the rule of three is made (directly proportional)

\frac{58.7}{y} = \frac{1}{2.63}
multiply cross
1*y = 58.7*2.63
y = 154.381\:g \stackrel{converting}{\longrightarrow}\:\boxed{y = 154381\:mg}


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At STP conditions, 0.25 moles of CO2(g), H2(g), NH3(g)

The answers are:
<span>1. Will contain the same number of molecules </span>
3. Will occupy the same volume

3 0
3 years ago
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The rate constant for a first-order reaction is 2.4 x 10-4 L/(mol's) at 600 K and 6.2 x 10-4L/(mol · s) at 900 K.
Alika [10]

Answer:

(R = 8.31 J/(mol · K)) 0.88 × 104 J/mol 1.42 × 102 J/mol 1.42 × 104 J/mol at 600 K and 6.2 × 10-4 L/(mol · s) at 900 K. Calculate the activation energy.

6 0
3 years ago
Determine the heat needed to warm 25.3 g of copper from 22 degrees celsius to 39 degrees celsius.
Serggg [28]

Answer:

The heat needed to warm 25.3 g of copper from 22°C to 39°C is 165.59 Joules.

Explanation:

Q=mc\Delta T

Where:

Q = heat absorbed  or heat lost

c = specific heat of substance

m = Mass of the substance

ΔT = change in temperature of the substance

We have mass of copper = m = 25.3 g

Specific heat of copper = c = 0.385 J/g°C

ΔT  = 39°C - 22°C = 17°C

Heat absorbed by the copper :

Q=25.3 g\times 0.385 J/g^oC\times 17^oC=165.59 J

The heat needed to warm 25.3 g of copper from 22°C to 39°C is 165.59 Joules.

5 0
3 years ago
An ordered list of chemical substances is shown.
alina1380 [7]

Answer : The correct option is, (C) 2, 4 and 5.

Explanation :

Combustion reaction : It is a type of reaction in which a hydrocarbon react with an oxygen molecule to give carbon dioxide, water as a product.

For example : Methane react with oxygen to give carbon dioxide and water.

CH_4+2O_2\rightarrow CO_2+2H_2O

In the given list of chemical substances, CuO,Cu_2O,Li_2O are in oxide form. They can not be both reactant and product of a single combustion reaction.

In the given list, C_2H_5NH_2 is the only hydrocarbon which shows a combustion reaction. That means C_2H_5NH_2 react with O_2 to give CO_2,H_2O and N_2 as a product.

The balanced combustion reaction of C_2H_5NH_2 is,

20C_2H_5NH_2+40O_2\rightarrow 40CO_2+7H_2O+10N_2

Therefore, the correct answer is, (C) 2, 4, and 5.

8 0
3 years ago
Example of oxidizing agents include
Ivahew [28]

Explanation:

Substances generally tends to specialize as either oxidizing or reducing agents.

An oxidizing agent is an electron acceptor which causes a co-reactant to be oxidized in a reaction.

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learn more:

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