Answer:
a.) Between 0.5 and 3 seconds.
Step-by-step explanation:
So I just went ahead and graphed this quadratic on Desmos so you could have an idea of what this looks like. A negative quadratic, and we're trying to find when the graph's y-values are greater than 26.
If you look at the graph, you can easily see that the quadratic crosses y = 26 at x-values 0.5 and 3. And, you can see that the quadratic's graph is actually above y = 26 between these two values, 0.5 and 3.
Because we know that the quadratic's graph models the projectile's motion, we can conclude that the projectile will also be above 26 feet between 0.5 and 3 seconds.
So, the answer is a.) between 0.5 and 3 seconds.
Answer:
<h2>
43.4° and 46.6°</h2>
Step-by-step explanation:
x - measure of angle
x + 3.2° - measure of its complementary angle
Complementary angles adds to 90°
x + x + 3.2° = 90°
2x = 90° - 3.2°
2x = 86.8°
x = 86.8°÷2
x = 43.4°
x+3.2° = 43.4° + 3.2° = 46.6°
Answer:
yes it is not b/c
Step-by-step explanation:
if n is >5 ,5 is < n
This is pretty much 75% of 55.5 which is 41.625. Rounding that up would make $41.63.