Answer:
m = 57.581 g
Explanation:
The actual yield or experimental yield of a reaction is always calculated using the theorical yield and the experimental, using the following expression:
%yield = Exp yield/theo yield * 100 (1)
If we know the theorical yield and the percent of yield, we can calculate the experimental or actual yield by solving the expression above:
Exp yield = %yield * theo yield/100
Replacing the values we have:
Exp yield = 81.1 * 71 / 100
Exp yield = 57.581 g
And this would be the actual yield of the reaction
The molecular formula C₅H₁₀O₅ and The scaling factor =5
<h3>Further explanation</h3>
Given
Molar mass = 150 g/mol
The empirical formula = CH₂O
Required
The scaling factor
Solution
The empirical formula is the smallest comparison of atoms of compound forming elements.
A molecular formula is a formula that shows the number of atomic elements that make up a compound.
(empirical formula) n = molecular formula
<em>n = the scaling factor</em>
(CH₂O)ₙ=150 g/mol
(12+2+16)ₙ=150
(30)ₙ=150
n=5
The molecular formula : C₅H₁₀O₅
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