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3 years ago

Is f(x)=x^2-3x+2 even function

Mathematics

1 answer:

Len [333]3 years ago

7 0

Answer:

Step-by-step explanation:

No, it is not an even function. The graph is not symmetric about the y-axis.

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Solve x2 = 12x – 15 by completing the square. Which is the solution set of the equation? Solve x2 = 12x – 15 by completing the s

Svetlanka [38]

Answer: $6+\sqrt{21}\ \text{and}\ 6-\sqrt{21}$

Step-by-step explanation:

Given

Quadratic equation is

$x^2-12x+15=0$

Solving by completing the square method

$\Rightarrow x^2-2\cdot 6\cdot x+15=0\\\text{add and subtract 36}\\\Rightarrow x^2-2\cdot 6\cdot x+15+36-36=0\\\Rightarrow x^2-2\cdot 6\cdot x+36+(-36+15)=0\\\text{using}\ (a-b)^2=a^2+b^2-2ab\\\Rightarrow (x-6)^2-21=0\\\Rightarrow (x-6)^2=21\\\Rightarrow x-6=\pm \sqrt{21}\\\Rightarrow x=6\pm \sqrt{21}$

The solution set of the equation is $6+\sqrt{21}\ \text{and}\ 6-\sqrt{21}$

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Pavlova-9 [17]

Answer:

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Step-by-step explanation:

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The table shows the number of cups of water required when cooking different amounts of rice

Ad libitum [116K]

Please explain more your question

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3 years ago

1x10+3×1+4×(1over1000)

Marina86 [1]

Answer:

14 and 4/1000 or 14004/1000

Step-by-step explanation:

1*10+3*1+4*(1/1000)

First i like to separate the equation by PEMDAS or order of operations. First is parentheses, which is the fraction. Then is exponents. There is none. Then multiplication and division so u solve 1*10, 3*1 and 4*1/1000.

This is the updated equation: 10+4+(4/1000)

Next you do subtraction and addition. The order does not matter if there's only addition. If there is subtraction u solve by the order of the equation. SO in this step we solve 10+4+(4/1000)

Here is the updated version: 14+(4/1000)

Then u add that which is 14 and 4/1000 or you can do 14004/1000

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3 years ago

A cabinetmaker buys 3.5 liters of oak varnish. The varnish costs $4.95 per liter. How much does 0.5 liters of varnish cost?

victus00 [196]

Answer:

$2.47

Step-by-step explanation:

The cabinetmaker would have paid $13.31 for everything.

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