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mina [271]
3 years ago
9

Hen solving a system of two linear equations in two​ variables, all variables subtract out and the resulting equation is 0 equal

s=8. what does this​ mean?
Mathematics
1 answer:
Jobisdone [24]3 years ago
3 0
It means there are no solutions to the equations
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Can i get help? Don’t really understand.
Rufina [12.5K]

First option: correct. This is because angles WOX and XOZ are supplementary, so

m\angle WOX=180^\circ-104^\circ=76^\circ

Second option: correct. By the inscribed angles theorem, we have

m\angle XWZ=m\angle XYZ=\dfrac{113^\circ}2=56.5^\circ

Angles WOX and YOZ are congruent because they form a vertical pair; they both have measure 76 degrees. This means angles WXY and WZY are also congruent, since the interior angles of any triangle sum to 180 degrees in measure. Therefore triangles WXO and YZO form a side-side-side pair, and all SSS triangles are similar.

Third option: not correct. There is a theorem (not sure what the name is) regarding intersecting chords that asserts the average of the measures of arcs WY and XZ is the same as the measure of angle XOZ. This means

\dfrac{m\widehat{WY}+113^\circ}2=104^\circ\implies m\widehat{WY}=95^\circ

Fourth option: not correct. This is because arcs WX and XZ are not "supplementary" in the sense that they do not form a semicircle and their measures do not add to 180 degrees. We know this because it's clear that point O is not the center of the circle. If it was, then angle XOZ would be a central angle and its measure would be the same as the arc XZ it subtends.

Fifth option: correct. The theorem mentioned in the assessment of the third option makes itself useful here. We have

\dfrac{m\widehat{WX}+m\widehat{YZ}}2=m\angle WOX\implies m\widehat{WX}+m\widehat{YZ}=2\cdot76^\circ=152^\circ

4 0
3 years ago
Simplify 5^3/5^7 leaving your anwser in index form
sveta [45]

Answer:  (5^3) / (5^7) = 5^ -4

or

1 / 5^4

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Michael spent $18 at a local farmers’ market. Apples cost $2 each and peppers cost $3 each.
boyakko [2]
2a+3p=18 because you don’t know how many apples or peppers you bought, all you know is how much money in total you spent which is $18
4 0
3 years ago
Read 2 more answers
There are three types of triangles on the basis of angles and three types on the basis of sides. How many different types of tri
balu736 [363]

Answer:

Acute, Obtuse and right angled triangle are the three triangles on the basis of angles.

Equilateral, Isosceles and Scalene are three triangles on the basis of of sides.

The seven types of triangles that exist in the world: equilateral, right isosceles, obtuse isosceles, acute isosceles, right scalene, obtuse scalene, and acute scalene.

7 0
4 years ago
It has been observed that a large percentage of professional hockey players have birthdays in the first part of the year. It has
vagabundo [1.1K]

Answer:

a

\mu  =  127

b

\sigma  =  9.76  

c

z-score  =  3.18

d

Yes, 158 players out of 508 is an unusual number of men born in the first 3 months of the year because the z score of 158  is  greater than  3( Note :the probability of  z-score = 3 is  97%)

e

The correct option is  option 3

Step-by-step explanation:

From the question we are told that

   The population proportion is  p =  0.25

   The sample size is  n =  508

   

Generally the mean is  mathematically represented as  

     \mu  =  np

=>   \mu  =  508 * 0.25

=>   \mu  =  127

Generally the standard deviation is mathematically represented as

     \sigma  =  \sqrt{ np (1-p)}

=>   \sigma  =  \sqrt{ 508 * 0.25 (1-0.25)}    

=>    \sigma  =  9.76  

Generally the z-score of  158 is mathematically represented as

    z-score  =  \frac{158 - 127}{9.76}

=>  z-score  =  \frac{158 - 127}{9.76}

=>  z-score  =  3.18

Yes, 158 players out of 508 is an unusual number of men born in the first 3 months of the year because the z score of 158  is  greater than  3( Note :the probability of  z-score = 3 is  97%)

What this means is that the almost the whole  professional hockey league player are born in the first month which is unusual

7 0
3 years ago
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