Slope=3, Y-intercept=(0,-1)
19, because a negitive and a negive is a postive so you are going to add them instead of subtract them. Hope i could help :) <3
<span>1/2x+3y/4=5 => (1/2)x + (3/4)y = 5
1/5x+3y/2=2 => (1/5)x + (3/2)y = 2
Eliminate the fractional coefficients: Mult. the first equation by 4 and mult. the second equation by 10:
2x + 15y = 20
</span><span>Multiply the 1st equation by -1:
-</span>2x - 3y = -20
2x + 15y = 20
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12y = 0, so y = 0. Then the first equation becomes 2x + 3(0) = 20, or
x=10.
Solution is (10,0).
Answer: (0,3)
Step-by-step explanation: To find the x-value of the vertex for any quadratic, you can use the formula -b/2a. In this case, there is no clear b, but you can think of it like y=-x^2 +0x+3 so in the form ax^2 + bx +c, b=0. Therefore the x-value is 0/ -2, or 0. So we know the vertex is (0, y). To find y, just plug 0 into the original equation for x, getting you y=0+3, so y=3, so the vertex is (0,3)
