Answer:
Write seven and twelve hundredths in standard form.
Step-by-step explanat
Answer:
Jogging 6th time.
Step-by-step explanation:
We have been given that Vicki started jogging the first time she ran she ran 3/16 mile the second time she ran 3/8 mile and the third time she ran 9/16 mile.
We can see that the distance Vicki covers each time forms a arithmetic sequence, where 1st term is 3/16.
We know that an arithmetic sequence is in form
, where,
= nth term of sequence,
= 1st term of sequence,
n = Number of terms in sequence,
d = Common difference.
Let us find common difference of our given sequence as:

Since Vicki needs to cover more than 1 mile, so we nth term of sequence should be greater than 1.

Let us solve for n.





We can also write next terms of our sequence as:

Therefore, Vicki will run more than 1 mile when she is jogging for 6th time.
Answer:
TheaterMania, basically you are getting more popcorn for $1, thats how did it.
Answer:
The fraction of smoothies sold were either banana or strawberry is 
Step-by-step explanation:
Given:
Of the smoothies sold yesterday at Marlins smoothie shop, 5/6 were banana and another 1/12 were strawberry.
Now, to find the fraction of the smoothies sold were either banana or strawberry.
Fraction of smoothie were of banana = 
Fraction of smoothie were of strawberry = 
Now, to get the fraction smoothies sold were either banana or strawberry by adding both the fractions of banana and strawberry:

Therefore, the fraction of smoothies sold were either banana or strawberry is 
20100 = 16000 * (1.02)^ t
20100/16000 = 1.02^t
1.25625 = 1.02^t
log 1.25625 = t * log 1.02
t = log 1.25625 / log 1.02
= 11.5