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3 years ago

What is the speed of a wave in a medium where a 1200 Hz frequency produces a 0.65 m wavelength?

Physics

1 answer:

Vanyuwa [196]3 years ago

4 0

Answer:

780 $ms^{-1}$

Explanation:

The equation used to find the speed of a waveform is V = f λ

You are given

f = 1200Hz

λ = 0.65m

and need to find V

Plug in your values to the equation

V = 1200 * 0.65

V = 780 $ms^{-1}$

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Define heat capacity of a substance. Write the S.I unit of heat capacity.

creativ13 [48]

Define heat capacity of a substance:

The heat capacity of a substance can be defined as the amount of heat required to change its temperature by one degree.

Write the S.I unit of heat capacity:

Joule per Kelvin

$\: \: \:$

Joule per Celsius

$\: \: \:$

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6 0

2 years ago

Consider the following cyclic process carried out in two steps on a gas. Step 1: 44 J of heat is added to the gas, and 20. J of

notka56 [123]

Answer:37 J

Explanation:

Given

Step :1

Heat added Q=44 J

Work done=-20 J

$\Delta E_1=Q+W=44-20=24 J$

Step :2

Heat added Q=-61 J

work done $W_2$

$\Delta E_2=Q+W_2$

$\Delta E_2=61+W_2$

$\Delta E_1+\Delta E_2=0$

as the process is cyclic

$44-20-61+W_2=0$

$W_2=37 J$

work done in compression is 37 J

3 0

3 years ago

An atom of uranium 238 emits an alpha particle (an atom of He) and recoils with a velocity of 1.895 * 10^ 5 m/sec . With velocit

lora16 [44]

Answer: The velocity of released alpha particle is $1.127\times 10^7m/s$

Explanation:

According to law of conservation of momentum, momentum can neither be created nor be destroyed until and unless, an external force is applied.

For a system:

$m_1v_1=m_2v_2$

where,

$m_1\text{ and }v_1$ = Initial mass and velocity

$m_2\text{ and }v_2$ = Final mass and velocity

We are given:

$m_1=238u\\v_1=1.895\times 10^{5}m/s\\m_2=4u\text{ (Mass of }\alpha \text{ -particle)}\\v_2=?m/s$

Putting values in above equation, we get:

$238\times 1.895\times 10^5=4\times v_2\\\\v_2=\frac{238\times 1.895\times 10^5}{4}=1.127\times 10^7m/s$

Hence, the velocity of released alpha particle is $1.127\times 10^7m/s$

4 0

3 years ago

A standing wave has a frequency of 471 Hz and a wavelength of 1.9. What is the speed of the

Brums [2.3K]

Answer:

c = 894.90 m/s

Explanation:

Given data:

Frequency of wave = 471 Hz

Wavelength of wave = 1.9 m

Speed of wave = ?

Solution:

Formula:

Speed of wave = frequency × wavelength

c = f×λ

c = 471 Hz × 1.9 m

Hz = s⁻¹

c = 471s⁻¹ × 1.9 m

c = 894.90 m/s

The speed of wave is 894.90 m/s.

6 0

3 years ago

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Tcecarenko [31]

The answer of this question is B.

5 0

3 years ago