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goldfiish [28.3K]
3 years ago
7

A weightlifter curls a 30 kg bar, raising it each time a distance of 0.50 m .How many times must he repeat this exercise to burn

off the energy in one slice of pizza? Assume 25% efficiency. Energy content of one slice of pizza is 1260 kJ.
Physics
1 answer:
ludmilkaskok [199]3 years ago
4 0

Answer:

N = 2141 times

Explanation:

Each time the work done to raise a given mass is

W = mgh

here we know that

m = 30 kg

h = 0.50 m

now we have

W = (30 kg)(9.81 m/s^2)(0.50)

W = 147.15 J

since it is just 25% of actual energy consumed as we know its efficiency is 25%

so we have total energy consumed in this way

E_{total} = \frac{147.15}{0.25}

E_{total} = 588.6 J

now if it took N number of times so burn the fat of a pizza then

N(588.6) = 1260 \times 10^3

N = 2141 times

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What is the current I(3τ), that is, the current after three time constants have passed? The current in the circuit will approach
Olin [163]

Complete Question

The complete question is shown on the first uploaded image

Answer:

a

I(\tau)=0.051 A

b

I(3 \tau)=0.076 A

c

I_c= 0.08 A

Explanation:

From the question we are told that

                I(t) = \frac{e}{R}(1-e^{\frac{t}{\tau} }) ; \ Where \ \tau = L/R

From the question we are told to find I(\tau) when t=0  equals the time constant (\tau)

That is to obtain I(\tau).This  is mathematically represented as

                   I(\tau = t)  = \frac{\epsilon}{R} (1- e^{-\frac{\tau}{\tau} })

             Substituting 12 V for \epsilon and 150Ω for R

                     I(\tau) = \frac{12}{150} (1- e^{-1})

                            =0.051 A

From the question we are told to find I(3 \tau) when t=0  equals the 3 times the  time constant (\tau)

That is to obtain I(3\tau).This  is mathematically represented as

                 I(\tau = t)  = \frac{\epsilon}{R} (1- e^{-\frac{3\tau}{\tau} })

                  I(\tau) = \frac{12}{150} (1- e^{-3})

                        =0.076 A

As tends to infinity \frac{\infty}{\tau}  = \infty

So I_c would be mathematically evaluated as

               I_c=I(\infty) = \frac{12}{150} (1- e^{- \infty})

                   = \frac{12}{150}

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4 years ago
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Answer:

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3 years ago
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Answer:

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5 0
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