Answer:
0.057 joules is needed to create the total rotational energy each second.
Explanation:
The energy rate is the ratio of total energy to time, which coincides with the definition of power at constant rate:
0.057 joules is needed to create the total rotational energy each second.
Answer:
Interneurons
Explanation:
An interneuron or integrative neuron is a central nervous system neuron, usually small and short axon, that interconnects with other neurons; but never with sensory receptors or muscle fibers, allowing more complex functions.
The interneuron, also called the association neuron, has the function of analyzing sensory information and storing part of it. It also acts on reflex acts, transforming a stimulus in response at the level of the spinal cord. They are located between sensory and motor neurons and are located in the upper nerve centers. Interneurons are multipolar neurons, which connect afferent neurons with efferent neurons in the neuronal or nerve tracts. In other words, they function as a communicational bridge, intercommunicating sensory neurons with motor neurons. Like motor cells, interneurons are only found in the central nervous system. In contrast to the peripheral nervous system, all CNS neurons appear to be interneurons, as they are in communication with many other neurons. However, the term "interneuron" refers to neurons that have axon and dendritic extensions of local extension and not distant, that is, short.
Well the object will have no Momentum since it is not moving, so a small object that is going 10 mph will have Momentum.
Answer:
c) 10.7m/s
Explanation:
From the exercise we know that at 5m the ball is traveling at 4m/s
To calculate its initial velocity we need to solve the following equation:
Since the initial height is 0
Solving for 
Answer:
Acceleration = 2.35 m/
Speed = 8.67 m/s
Explanation:
The coefficient of friction , u =0.3
The angle of incline = 30°
The two forces acting on block are weight and friction.
weight along the incline = mg cos60° = 
= 0.5 mg
Friction along incline = umg cos30° = mg 
Friction along incline = 0.26 mg
Net force acting on the weight = (0.5 - 0.26) mg = 0.24 mg
Acceleration = 
= 0.24 g = 2.35 m/
The height of incline = 8 m
Length of the inclined edge = 16 m
v= 8.67 m/s
