In this case, 58.703 has five significant figures because the 3 at the end is significant and therefore makes the 0 significant as well. Since there are 5 significant figures, we need to round off the 7 to get 58.7, which has three significant figures.
Hope this helps.
Answer:
Iron (iii) chloride reacts with copper (ii) sulfate to give iron sulfate and copper chloride.
Explanation:
The balanced equation of iron iii chloride+ copper ii sulfate is as follows.
The number of atoms present in 0.10 mol of PtCl2(NH3) is calculated using Avogadro law formula
that is
1 mole = 6.02 x10^23 atoms
what about 0.10 moles = ? atoms
= 6..02 x10 ^23 x 0.1 = 6.02 x10^22 atoms
The answer for this one would be A because
