The decay product represented by X : Thorium (Th) : ²³⁴₉₀Th
<h3>Further explanation</h3>
Given
Decay reaction
²³⁸₉₂U ⇒ ⁴₂He + X
Required
The decay product
Solution
Radioactivity is the process of unstable isotopes to stable isotopes by decay, by emitting certain particles,
- alpha α particles ₂He⁴
- beta β ₋₁e⁰ particles
- gamma particles ₀γ⁰
- positron particles ₁e⁰
- neutron ₀n¹
In a decay reaction, <em>the sum of the mass number and atomic number of the elements in the reactants and products must be the same</em>
So the mass number of the element X = 238 - 4 = 234
Atomic number of the element X = 92 - 2 = 90
If we look at the periodic system, then the element with atomic number 90 is Thorium (Th)
In the given situation, the reaction is-
NO + H2 ↔ Products
The rate of the reaction can be expressed (in terms of the decrease in the concentration of the reactants) as-
Rate = -dΔ[NO]/dt = -dΔ[H2]/dt
Now, if the concentration of NO is decreased there will be fewer molecules of the reactant NO which would decrease the its collision with H2. As a result the rate of the forward reaction would also decrease.
Ans) A decrease in the concentration of nitrogen monoxide decreases the collisions between NO and H2 molecules. the rate of the forward reaction then decreases.
Answer:
iam pretty sure it's 3, since the water boils from the bunsen burner