Answer:
Option A = 2.2 L
Explanation:
Given data:
volume of one mole of gas = 22.4 L
Volume of 0.1 mole of gas at same condition = ?
Solution:
It is known that one mole of gas at STP occupy 22.4 L volume. The standard temperature is 273.15 K and standard pressure is 1 atm.
For 0.1 mole of methane.
0.1/1 × 22.4 = 2.24 L
0.1 mole of methane occupy 2.24 L volume.
Answer:
8.4) 27.1 cm³
8.5) 0.217 mol/dm³
Explanation:
Please see attached picture for full solution.
8.4) Since the results from titrations 3-5 are within 0.10cm³ from each other, these 3 results are concordant.
8.5) Find mol of sulfuric acid to find mol of NaOH using mole ratio. Equation has already been balanced for you, so mole ratio of NaOH to H2S04 is 2:1. To find concentration of NaOH, divide the number of moles by the volume in dm³ since the units for concentration is mol/dm³, which you can think of as the number of moles of NaOH in a dm³ of solution.
1 dm³ = 1000cm³
Thus, 1cm³= 1/1000 dm³
Answer:
A.
Explanation:
Water was added to the reaction after the completion of the reaction so as to lower the solubility if the product in the solution therefore, the product can be precipitated out. On adding water the reaction moves in forward direction and more product is formed. (By Le Chatelier's principle). Thus, the precipitation occurs. Hence, option A is correct.
Answer:
Explanation:
Seven of these isomers having similar pKa values are as follows
1) CH₃ -CH(CH₃)-CH(NO₂)-CH₃
2 ) CH₃ -(CH₂)-CH(NO₂)-CH₂-CH₃
3 ) CH₃ -CH₂-CH₂-CH₂-CH₂-NO₂
4 ) CH₃ -CH₂-CH₂-CH(NO₂)-CH₃
5 )CH₃ -CH(CH₃)(NO₂)-CH₂-CH₃
6 ) CH₃ -CH(CH₃)-CH₂-CH₂-NO₂
7)CH₃ -CH₂-CH₂-CH(CH₃)-NO₂
CH₃-C(CH₃)₂-NO₂
The last isomer has different PKa value because of tertiary carbon attached to nitro group.
