Answer:
"Subsoil" is the correct answer.
Explanation:
- The method of transforming sediments become rocky solids is considered as Lithification. The floor stratum or level below the upper floors at the base of the floor is a Subsoil.
- Sediments comprise materials particles like sand, pebbles, skeletons kind of bones as well as muck, that were transported and produced instead in water or perhaps wind someplace.
Answer is: sodium bicarbonate is the limiting reagent.
Balanced chemical reaction:
3NaHCO₃(aq) + H₃C₆H₅O₇(aq) → 3CO₂(g) + 3H₂O(l) + Na₃C₆H₅O₇(aq).
n(NaHCO₃) = m(NaHCO₃) ÷ M(NaHCO₃).
n(NaHCO₃) = 1.50 g ÷ 84 g/mol.
n(NaHCO₃) = 0.0178 mol.
n(H₃C₆H₅O₇) = 1.50 g ÷ 192.12 g/mol.
n(H₃C₆H₅O₇) = 0.0078 mol.
From chemical reaction: n(NaHCO₃) : n(H₃C₆H₅O₇) = 3 : 1.
n(NaHCO₃) : 0.0078 mol = 3: 1.
n(NaHCO₃) = 0.0234 mol; amount of substance need to react with citric acid, so we conclude there is no enough sodium bicarbonate.
Answer:
713.33 g/mol
Explanation:
The<em> freezing-point depression equation</em> is:
Where ΔT is the difference in temperature. The freezing point of pure benzonitrile is -12.75 °C, so ΔT = -12.75 - (-13.8) = 1.05 °C
Kf is the cryopscopic constant, which is 5.35 °C/m (as reported by the CRC Handbook).
m is the molality (moles compound X/kg benzonitrile).
So first we <u>calculate the molality</u>:
Now we <u>calculate the moles of X that were added</u>:
75 g ⇒ 75/1000 = 0.075 kg
- 0.196 m = mol X / 0.075 kg
Finally we <u>calculate the molar mass of X</u>, using the added mass:
- 10.5 g / 0.0147 mol = 713.33 g/mol
Answer:
Barium Hydroxide
Explanation:
..........................