Yes the same set uo because
mass = grams
Using the
V1/T1=V2/T2
where
T1=50C= 323.15K
T2= -5C=268.15 K
V2= 212m^3
substitute the given values, we will get the initial volume
V1=V2T1/T2
V1= 255.48m^3
The initial volume is 255.48m^3
Answer:
Look at sheet
Explanation:
Ight so like I'm too lazy to type this out just look at my work. Idk why it works I just know it works
For many (but not all) problems, you can simply round the atomic weights and the molar mass to the nearest 0.1 g/mole. HOWEVER, make sure that you use at least as many significant figures in your molar mass as the measurement with the fewest significant figures. In other words, never let your molar mass be the measured value that determines how many signficant figures to use in your answer!
Answer:
Moisture content in wet basis = 47.4 %
Explanation:
<u>Moisture content expresses the amount of water present in a moist sample.</u> <u>Dry basis and wet basis are widely used to express moisture content. </u>
The next equation express the moisture content in wet basis:

<em>where,
: moisture content in wet basis and </em>
<em>
: moisture content in dry basis </em>
We now calculate the moisture content in wet basis:

= 0.474 = 47.4 % wet basis
Have a nice day!