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Butoxors [25]
4 years ago
15

Please Help Me.

Mathematics
1 answer:
aksik [14]4 years ago
5 0

Answer:

1) First mistake: 29 - 5 = 24, not -24

Second mistake: Division by negative number changes the sign of inequality. Sam didn't change the sign.

2) 2.5 kg

3) a) no solutions

b) one solution

c) infinitely many solutions

Step-by-step explanation:

1)Sam solved the following problem:

-4x+5>29\\ \\-4x+5-5>29-5\ [\text{Sam used the addition property}]\\ \\-4x>24\ [\text{Here Sam made a mistake, because }29-5=24\text{ not }-24]\\ \\\dfrac{-4x}{-4}

Dividing by negative number changes the sign of the inequality.

Thus,

x

2) Hillary buys 3 pounds of Gala apples which cost $4.50 per pound and paid

\$4.50\cdot 3=\$13.50

Let x be the number of pounds of Granny Smith apples Hillary bought. She paid $4.50x for x pounds of Granny Smith apples.

The total cost of Hillary buying is $24.75, so

\$4.50x+\$13.50=\$24.75

Solve this equation

\$4.50x=\$24.75-\$13.50\\ \\4.50x=11.25\\ \\x=2.5\ kg

of Granny Smith apples.

3) Consider all equations:

a) 6x+8=6(x+2)

Use distributive property:

6x+8=6x+12\\ \\6x+8-6x=6x+12-6x\\ \\8=12

You get false equality, so this equation has no solutions.

b) 10x=15+5x

Add -5x:

10x-5x=15+5x-5x\\ \\5x=15\\ \\x=3\ [\text{Divide by 5}]

This equation has one solution

c) x+11=8x+11-7x

This equation is equivalent to

x+11=(8x-7x)+11\\ \\x+11=x+11\\ \\x+11-11=x+11-11\\ \\x=x\\ \\x-x=x-x\\ \\0=0

You get the equality that is true for all values of x, so the equation has infinitely many solutions.

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Step-by-step explanation:

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(6x10^2)/(3x10-5) help what is this in standard form?
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<u>Answer: </u>

The standard form of \frac{6 \times 10^{2}}{3 \times 10^{-5}} is 20,00,0000

<u>Solution: </u>

Given that \frac{6 \times 10^{2}}{3 \times 10^{-5}} ---- eqn 1

To write\frac{6 \times 10^{2}}{3 \times 10^{-5}} in standard form,

We know that \bold{\frac{1}{a^{-m}} = a^{m}} .So \frac{1}{10^{-5}}  becomes 10^{5}.

Now eqn 1 becomes,

= \frac{6 \times 10^{2}}{3} \times 10^{5} ----- eqn 2

We know that \bold{a^{m} \times a^{n}=a^{m+n}}, so 10^{2} \times 10^{5} = 10^{7}

Now eqn 2 becomes,

= \frac{6}{3} \times 10^{7}

= 2 \times 10^{7} ---- eqn 3

Expanding 10^{7}:  

Here 10 is the base term and 7 is the exponent value. So base term 10 is multiplied by itself 7 times.

10^{7} = 10 \times 10 \times 10 \times 10 \times 10 \times 10 \times 10

Now eqn 3 becomes,

= 2 \times 10 \times 10 \times 10 \times 10 \times 10 \times 10 \times 10

= 20,00,0000  

Hence the standard form of \frac{6 \times 10^{2}}{3 \times 10^{-5}} is 20,00,0000

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Answer:

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