To get the maximum height, we first determine the time at which this maximum height is attained by differentiating the given equation and equating the differential to zero.
h(t) = -0.2t² + 2t
Differentiating,
dh(t) = -(0.2)(2)t + 2 = 0
The value of t is equal to 5. Substituting this time to the original equation,
h(t) = -0.2(5²) + 2(5) = 5 ft
Thus, the maximum height is 5 ft and since it will take 5 seconds for it to reach the maximum height, the total time for it to reach the ground is 10 seconds.
Answers: maximum height = 5 ft
time to reach max height = 5 seconds
time it will reach the ground = 10 s
2(3w-2+w)
=2(4w-2)
=8w-4
the formula for solving perimeters is 2(WL). so L=3w-2, because the question said the length is 2 units shorter than 3 times the width, and the width is w. so the final equation is <span>2(3w-2+w), and then you just have to simplify that </span>
Answer:
i would say that the rocket was in the air for 8 seconds and the highest it went in the air was 48
Step-by-step explanation:
Answer:
1. 1/3 * 7 = 7/3 = 2 1/3 or two and one-third
2. 7/9 * 3/5 = (3*7)/(9*5) = 21/45
dividing numerator and denominator by 3
21/45 = 7/15 or start fraction seven over fifteen end fraction
3. 2 2/3 is equivalent to 8/3, then:
8/3 * 9 = 8 * 9/3 = 8 * 3 = 24
4. -4 1/2 is equivalent to -9/2
-2 1/3 = -7/3
Then:
-4 1/2 * (-2 1/3) = -9/2 * (-7/3) = -3/2 * (-7) = 21/2 = 10 1/2 or 10 one-half
5. (1/3) / (5/6) = 1/3 * 6/5 = 2/5 or two-fifths
6. 3 1/5 is equal to 16/5
16/5 ÷ 8 = 16/5 * 1/8 = 16/8 * 1/5 = 2 * 1/5 = 2/5 or The fraction is 2 over 5.
7. (-3/5) / (-3/4) = -3/5 * (-4/3) = 12/15
dividing each term by 3:
4/5 or The fraction is 4 over 5.
8. -3 1/5 si equivalent to -16/5
-3 1/5 ÷ 2/15 = -16/5 * 15/2 = -16/2 * 15/5 = -8 * 3 = -24
Answer:
33%
Step-by-step explanation:
60-45=15
15/45=0.33
0.33x100=33%
