F(x) = 4x^2 + 12
g(x) = x - 1
(f o g)(x) = f(g(x)) = 4(x - 1)^2 + 12 = 4(x^2 - 2x + 1) + 12 = 4x^2 - 8x + 4 + 12 = 4x^2 - 8x + 16
(f o g)(3) = 4(3)^2 - 8(3) + 16 = 4(9) - 24 + 16 = 36 - 8 = 28
Answer:
y+2=−3(x−1)
Step-by-step explanation:
y+2=-3(x-1)
y=-3x+3-2
y= -3x+1
Answer:
2nd option
{(-8, -2), (-4, 1), (0, -2), (2, 3), (4, -4)}
Step-by-step explanation:
For a function to exist, every value of input must have exactly one value of output.
The rest of the relations(1, 3, and 4) have 2 outputs for 1 input so they dont make a function.
Answer:
Try to search up euphemisms to help you in an argument where your forced to say no
Step-by-step explanation: In this situation apologize to them and say
I can't do that or no
