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3 years ago

PLEASE ANSWER FAST!15 POINTS. Jared drew a diagram to compare zygote and club fungi.

Chemistry

2 answers:

REY [17]3 years ago

7 0

Answer:

Explanation:

I hope this helps... ^-^

Licemer1 [7]3 years ago

3 0

Answer:

The answer is D, Have loosely arranged hyphae

Explanation:

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Calculate the area of a floor that is 1.5 × 103 m long and 2.2 × 102 m wide.

liubo4ka [24]

Answer:

154.5+224.4=378.9m

Explanation:

8 0

4 years ago

Could you guys help me with these questions pls. Thank you

lapo4ka [179]

Answer:

8.4) 27.1 cm³

8.5) 0.217 mol/dm³

Explanation:

Please see attached picture for full solution.

8.4) Since the results from titrations 3-5 are within 0.10cm³ from each other, these 3 results are concordant.

8.5) Find mol of sulfuric acid to find mol of NaOH using mole ratio. Equation has already been balanced for you, so mole ratio of NaOH to H2S04 is 2:1. To find concentration of NaOH, divide the number of moles by the volume in dm³ since the units for concentration is mol/dm³, which you can think of as the number of moles of NaOH in a dm³ of solution.

1 dm³ = 1000cm³

Thus, 1cm³= 1/1000 dm³

3 0

3 years ago

PLEASE HELP!!!

kogti [31]

Atomic no = no of electrons present in atom
and atomic mass = no of protons + no of neutrons

6 0

3 years ago

How many microliters are in 1 L? I n 20 mL?

pshichka [43]

1 liter= 1,000,000 microliters
20 mL= 20,000 microliter

I hope this helped ;)))

4 0

4 years ago

"Carbonyl fluoride, COF2, is an important intermediate used in the production of fluorine-containing compounds. For instance, it

Alex17521 [72]

Answer:

$\boxed{\text{0.50 mol/L}}$

Explanation:

The balanced equation is

2COF₂ ⇌ CO₂+CF₄; Kc = 9.00

1. Set up an ICE table

$\begin{array}{ccccc}\rm 2COF_{2} & \, \rightleftharpoons \, & \rm CO_{2} & +&\rm CF_{4}\\2.00& & 0& & 0\\-x& & +x & & +x\\2.00 - x& & x & &x \\\end{array}$

2. Solve for x

$K_{c} = \dfrac{[\rm CO][ \rm CF_{4}]}{[\rm COF_{2}]^{2}} = 9.00\\\\\begin{array}{rcl}\dfrac{x^{2}}{(2.00 - x)^{2}} & = & 9.00\\\dfrac{x}{2.00 - x} & = & 3.00\\x & = &3.00(2.00 - x)\\x & = & 6.00 - 3.00x\\4.00x & = & 6.00\\x & = & \mathbf{1.50}\\\end{array}$

3. Calculate the equilibrium concentration of COF₂

c = (2.00 - x) mol·L⁻¹ = (2.00 - 1.50) mol·L⁻¹ = 0.50 mol

$\text{The equilibrium concentration of COF$_{2}$ at equilibrium is $\boxed{\textbf{0.50 mol/L}}$}$

Check:

$\begin{array}{rcl}\dfrac{1.50^{2}}{0.50^{2}} & = & 9.00\\\\\dfrac{2.25}{0.25}& = & 9.00\\\\9.00 & = & 9.00\\\end{array}$

OK.

5 0

4 years ago