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kvasek [131]
4 years ago
9

How many microliters are in 1 L? I n 20 mL?

Chemistry
1 answer:
pshichka [43]4 years ago
4 0
1 liter= 1,000,000 microliters
20 mL= 20,000 microliter

I hope this helped ;)))
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Which formula represents a polar molecule
krek1111 [17]

Answer:

the formula that represents a polar molecule is NH3 the 3 is small and toward the bottom

8 0
3 years ago
The decomposition of nitrogen dioxide is described by the following chemical equation:
kow [346]

Answer:

The balanced chemical equation will be "NO_{2}+O\rightarrow NO+O_{2}".

Explanation:

The given equation is:

2NO_{2}\rightarrow 2NO+O_{2}

<u>Step 1:</u>

<u></u>2NO_{2}\rightarrow NO+O...(equation 1)

<u>Step 2:</u>

<u></u>NO_{2}+O\rightarrow NO+O_{2}...(equation 2)

On adding "equation 1" and "equation 2", we get

⇒  NO_{2}+NO_{2}+O\rightarrow NO+O+NO+O_{2}

⇒  2NO_{2}\rightarrow 2NO+O_{2}

The second step:

⇒  NO_{2}+O\rightarrow NO+O_{2}

3 0
3 years ago
A volume of 129 mL of hydrogen is collected over water. The water level in the collecting vessel is the same as the outside leve
mixas84 [53]

Explanation:

As it is given that water level is same as outside which means that theoretically, P = 756.0 torr.

So, using ideal gas equation we will calculate the number of moles as follows.

                  PV = nRT

or,           n = \frac{PV}{RT}

                 = \frac{\frac{756}{760}atm \times 0.129 L}{0.0821 Latm/mol K \times 298 K}

                  = 0.0052 mol

Also,  No. of moles = \frac{mass}{\text{molar mass}}

               0.0052 mol = \frac{mass}{2 g/mol}

                  mass = 0.0104 g

As some of the water over which the hydrogen gas has been collected is present in the form of water vapor. Therefore, at 25^{o}C

                P_{\text{water vapor}} = 24 mm Hg

                                = \frac{24}{760} atm

                                = 0.03158 atm

Now,   P = \frac{756}{760} - 0.03158

              = 0.963 atm

Hence,   n = \frac{0.963 atm \times 0.129 L}{0.0821 L atm/mol K \times 298 K}

                 = 0.0056 mol

So, mass of H_{2} = 0.0056 mol × 2

                         = 0.01013 g (actual yield)

Therefore, calculate the percentage yield as follows.

      Percent yield = \frac{\text{Actual yield}}{\text{Theoretical yield}} \times 100

                              = \frac{0.01013 g}{0.0104 g} \times 100            

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Thus, we can conclude that the percent yield of hydrogen for the given reaction is 97.49%.

3 0
3 years ago
Determine the potential deaths resulting from the following exposure to chlorine:
jekas [21]

Answer:

For each scenario as following:

A. 3 Potential deaths by chlorine exposure

B. 1 Potential deaths by chlorine exposure

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6 0
3 years ago
1. A gas sample at a pressure of 5.00 atm has a volume of 3.00 L. If the gas pressure is changed to 760 mm Hg, what volume will
tatyana61 [14]

Answer:

V₂ =  15.00 atm

Explanation:

Given data:

Initial pressure = 5.00 atm

Initial volume = 3.00 L

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Final volume = ?

Solution:

P₁V₁ = P₂V₂

V₂ = P₁V₁ /  P₂

V₂ =  5.00 atm × 3.00 L / 1 atm

V₂ =  15.00 atm

8 0
3 years ago
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