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choli [55]
3 years ago
8

A student calculates the volume of a graduated cylinder to be 43.26 ml. The actual volume is 42.32 ml. What is the percent error

? Show your work below. Round your answer to two digits.
Chemistry
1 answer:
Tpy6a [65]3 years ago
7 0

Answer:

2.2%

Explanation:

Percentage error,

You apply the formula,

[(Estimated value - Actual value)/Actual value] × 100%

; [(43.26 - 42.32)/42.32] × 100

; (0.94/42.32) × 100

; 0.022 × 100

Percent error = 2.2%

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Answer:

Let me give it a try.

H3PO4 + Ca(OH)2 = Ca3(PO4)2 + H2O

Balancing this reaction

2H3PO4 + 3Ca(OH)2 == Ca3(PO4)2 + 6H2O.

Moles= Molarity x Volume

Volume = 38.5ml = 0.0385L

Moles of Ca hydroxide = 0.150m/L x 0.0385L

(Notice the units canceling out...leaving moles).

=0.005775moles of Ca(OH)2.

From balanced reaction...

3moles of Ca(OH)2 completely reacts with 2moles of H3PO4

0.005775moles of Ca(OH)2 would completely react with....

= 0.005775 x 2/(3)

=0.00385moles of H3PO4.

Now we're looking for its Concentration in Mol/L

Molarity=Moles of solute/Volume of solution(in L)

Volume of solution assuming no other additions to the reaction = 15ml + 38.5ml =53.5ml =0.0535L

Molarity = 0.00385/0.0535

=0.072Mol/L.

If this is wrong

then Simply Try The formula for Mixing of solutions

C1V1 = C2V2

0.15 x 38.5 = C2 x (15+38.5)

C2 = 0.11M/L.

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What must happen for heat to be transferred by convection?
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Answer: The heat transfer by convection requires a solid-fluid interface, a temperature difference between the solid surface and the surrounding fluid and a motion of the fluid. The process of heat transfer by convection would occur when there is a movement of macro-particles of the fluid in space from a region of higher temperature to lower temperature.

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3 years ago
A 19-g piece of metal absorbs 186.75 joules of heat energy, and its temperature changes from 35°C to 175°C. Calculate the specif
slavikrds [6]

Answer:

0.0702J/g°C the specific heat capacity of the metal.

Explanation:m

Q=m\times c\times \Delta T=m\times c\times (T_{2}-T_{1})

where,

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m_1 = Mass of metal= 19 g

T_1 = Initial  temperature of metal = 35^oC

T_2 =Final  temperature of metal = 175^oC

c = specific heat of metal= ?

186.75 J=19 g\times c\times (175^oC-35^oC)

c=\frac{186.75 J}{19 g\times (175^oC-35^oC)}

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0.0702J/g°C the specific heat capacity of the metal.

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Option b.

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