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Naddika [18.5K]
3 years ago
10

Let f(x) = 4x + 5 and g(x) = x2 - 9x + 20. f(x) g(x)

Mathematics
1 answer:
Reil [10]3 years ago
7 0

Answer:97

97

Step-by-step explanation:

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I WILL GIVE BRAINLIEST TO WHOEVER IS CORRECT!!!!!!
melisa1 [442]
Match the whole number and the bottom fraction number and gets u answer!
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3 years ago
In response to a gss question in 2006 about the number of hours spent per day watching television, the responses by the fifteen
NemiM [27]

Answer:

Standard error = 0.4

Step-by-step explanation:

Step 1

We find the Standard Deviation

The formula = √(x - mean)/n - 1

n = 15

Mean = 1.93 hours

= √(0- 1.93)² + (0-1.93)² +(0- 1.93)²+( 0- 1.93)²+ (1- 1.93)² + (1- 1.93)² +(1 - 1.93)² +(2 - 1.93)² + (2 - 1.93)² + (2 - 1.93)² + (2 - 1.93)² + ( 2 - 1.93)² +(4 - 1.93)² +(4 - 1.93)² + (5 - 1.93)²/15 - 1

= √(3.737777776 + 3.737777776 + 3.737777776 + 0.871111111 +0.871111111 + 0.871111111 + 0.004444444445+ 0.004444444445 + 0.004444444445 + 0.004444444445 + 0.004444444445 + 1.137777778 + 4.271111112 + 4.271111112 + 9.404444446)/15 - 1

= √2.352380952

= 1.533747356

Step 2

We find the standard error

The formula = Standard Deviation/√n

Standard deviation = 1.533747356

n = 15

= 1.533747356/√15

= 1.533747356 /3.87298334621

= 0.39601186447

Approximately = 0.4

Therefore, the standard error is 0.4

4 0
3 years ago
Write a unit rate for the situation $44 in 4 days
Dmitry [639]

Answer:

$11 per day

Step-by-step explanation:

44÷4=11

...

6 0
4 years ago
Read 2 more answers
You are jumping off the 12 foot diving board at the municipal pool. You bounce up at 6 feet per second and drop to the water you
NARA [144]

Answer:

When do you hit the water?

1.075 seconds after you jump.

What is your maximum height?

the maximum height is 12.5626 ft

Step-by-step explanation:

The equation:

h(t) = -16*t^2 + 6*t + 12

Is the height as a function of time.

We know that the initial height is the height when t = 0s

h(0s) = 12

and we know that the diving board is 12 foot tall.

Then the zero in h(t)

h(t) = 0

Represents the surface of the water.

When do you hit the water?

Here we just need to find the value of t such that:

h(t) = 0 = -16*t^2 + 6*t + 12

Using the Bhaskara's formula, we get:

t = \frac{-6 \pm \sqrt{6^2 - 4*(-16)*12} }{2*(-16)} = \frac{-6 \pm 28.4}{-32}

Then we have two solutions, and we only care for the positive solution (because the negative time happens before the jump, so that solution can be discarded)

The positive solution is:

t = (-6 - 28.4)/-32 = 1.075

So you hit the water 1.075 seconds after you jump.

What is your maximum height?

The height equation is a quadratic equation with a negative leading coefficient, then the maximum of this parabola is at the vertex.

We know that the vertex of a general quadratic:

a*x^2 + b*x + c

is at

x = -b/2a

Then in the case of our equation:

h(t) = -16*t^2 + 6*t + 12

The vertex is at:

t = -6/(2*-16) = 6/32 = 0.1875

Evaluating the height equation in that time will give us the maximum height, which is:

h(0.1875) =  -16*(0.1875 )^2 + 6*(0.1875) + 12 = 12.5626

And the height is in feet, then the maximum height is 12.5626 ft

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3 years ago
The pressure exerted by a certain liquid at a certain point is directly proportional to the depth of the point beneath the surfa
Ivanshal [37]

Answer:

Calculate, in kPa, the pressure exerted by a column of water that is 10-m tall. Assume the weight density of water to be and ignore the pressure due to the atmosphere.

Step-by-step explanation:

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2 years ago
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