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klasskru [66]
2 years ago
15

Austin will rent a car for the weekend. He can choose one of two plans. The first plan has an initial fee of $40 and costs an ad

ditional $0.11 per mile driven. The second plan has an initial fee of $49 and costs an additional $0.09 per mile driven.
Mathematics
1 answer:
GenaCL600 [577]2 years ago
7 0

Answer:

1st plan--> 40+0.11x

2nd plan--> 49+0.09x

Dont know wat u want

Step-by-step explanation:

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What is the measure of the scale down below
EastWind [94]

Answer:

58 degrees

Step-by-step explanation:

It shows a square which means it is a right angle / 90 degrees. So that means because 32 degrees is already there the equation is 90 - 32 = 58 degrees.

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(200-50) + 50 * 2 in hurry
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Step-by-step explanation:

200-50=150+50=200*2=400

Are you just posting your questions for an assignment?

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Write the number 0.000938 in scientific notion.
ss7ja [257]
<span>0.000938 in scientific notion.

First we need to move the decimal to its right and we need a number which is between 1-10. 

0.000938
00.00938
000.0938
0000.938
00009.38

We moved the decimal 4 times and to the right so it will be negative. -4.


9.38 </span>× 10^-4

Scientific notation of 0.000938 is 9.38 × 10^-4.

Check:-

9.38 × 10^-4 = <span>0.000938
</span>0.000938 = <span>0.000938
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<span>Scientific notation of 0.000938 is 9.38 × 10^-4.</span>
6 0
3 years ago
Determine if each pair or ratio or rate is equivalent. 16 out of 28 and 240 of 560
Keith_Richards [23]

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5 0
3 years ago
Erica is participating in a road race. The first part of the race is on a 5.2-mile-long straight road-oriented at an angle of 25
kap26 [50]

Answer:

6.31 mi

Step-by-step explanation:

The diagram below explains the solution better.

From the diagram,

C = starting point of the race.

A = end of the first part of the race.

B = end of the race.

Using Cosine rule, we can find the straight-line distance between the starting point and the end of the race.

Cosine rule states that:

a^2 = b^2 + c^2 - 2bc[cos(A)]

where A = angle A = <A

Given that

b = 5.2 miles

c = 2.0 miles

<A = 115° (from the diagram)

Hence,

a^2 = 5.2^2 + 2.0^2 - 2*5.2*2.0[cos(115)]\\\\a^2 = 27.04 + 4 - 20.8[cos(115)]\\\\a^2 = 31.04 + 8.79\\\\a^2 = 39.83\\\\a = \sqrt{39.83}\\ \\a = 6.31 mi

The straight-line distance between the starting point and the end of the race is 6.31 mi

4 0
3 years ago
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