Okay, so the angle of K is 45° (180 - 135).
Draw a line that goes straight down from angle L and let's say that point is point Z. You can see that this triangle can be separated into two special triangles: the 45 45 90 triangle on the left (ΔLKZ) and the 30 60 90 triangle (ΔLMZ) on the right.
I don't know if you've learned this yet (just google them if you're confused): - for a 45 45 90 triangle the sides are x, x, and x√2. - for a 30 60 90 triangle the sides are x, 2x, and x√3.
Since we know that LM is 20√3, using the 30 60 90 trick, you can see that LZ is 10√3 and MZ is 30.
Next, since LZ is 10 sqrt(3), using the 45 45 90 trick, <em>KL is 10√6</em> and KZ is 10 sqrt(3). Therefore, KM = KZ + MZ = <em>10√3 + 30</em>
<u>The answer: KL is 10√6, KM is 10√3 + 30</u>
(I'm sorry it's such a long explanation, pictures would have been better)
Answer:
it would for sure be a
Step-by-step explanation:
Answer:
1.
P(E1)=P(E2)=P(E3)=P(E4)=P(E5= )1/5
2.
P(E1)=0.4
P(E2)= 0.26
P(E3)=0.34
3.
No the probability assignments are invalid
Step-by-step explanation:
1
Total number of possible outcomes = 5
<u>Equation (4.3)</u>
0< P(Ei)<1
<u>Equation (4.4)</u>
P(E1) + P(E2) +........+P(En)=1
As the outcomes are equally likely therefore,
Probability for each outcome= P(Ei) = 1/5
2
Total number of outcomes = 50
Outcomes for event E(1)= 20
Outcomes or event E(2)= 13
Outcomes or event E(3) = 17
P(Ei)= (number of outcomes for event Ei/ Total number of outcomes)
P(E1)=20/50=0.4
P(E2)= 13/50=0.26
P(E3)=17/50=0.34
3
P(E1) .10,
P(E2) .15,
P(E3) .40,
P(E4) .20
0.1 +0.15+0.40+0.20=0.85<1
According to equation (4.4) the probability assignments are invalid as the sum of probabilities for all outcomes must be equal to 1.
Step-by-step explanation:
1 in 4
The probability (likelihood) of getting two heads is 1 in 4 (. 25).
Answer:
GH ≈ 12.5 ft
Step-by-step explanation:
Using the sine ratio in the right triangle
sin34° = 
= 
= 
( multiply both sides by GH )
GH × sin34° = 7 ( divide both sides by sin34° )
GH = 
≈ 12.5 ft ( to the nearest tenth )
