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Radda [10]
3 years ago
13

Graph y = 1/3x + 3. Can someone help me with this question ​

Mathematics
1 answer:
xxTIMURxx [149]3 years ago
8 0

Answer:

Points are (-9, 0 ) and (0, 3) then draw a line through both points.

Step-by-step explanation:

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Find n. 8/12 = n/48. n = ?
Novosadov [1.4K]

Answer:

n = 32

Step-by-step explanation:

<u><em>Given:</em></u>

<u><em></em></u>\frac{8}{12}=\frac{n}{48}

<u><em>Solve:</em></u>

<em />\mathrm{Cross\; Multiply:}

<em />\frac{8}{12}=\frac{n}{48}

\mathrm{48\times8=384}

\mathrm{384\div12=32}

\mathrm{Hence,n=32}

~\mathrm{[Kavinsky]}

7 0
3 years ago
Read 2 more answers
What is the answer? I don’t understand how to get it.
miss Akunina [59]

Answer:

A.

Step-by-step explanation:

Sub in the (x,y) points given into the equation to see if true ....you'll find A is the answer

Example  point (3,95 )      95 =  -10.375 (3) + 126.125    ??  

                                           95 = 95     Check !

               then try the other point ( 11,12) to be sure ....

             

5 0
2 years ago
If one movie ticket cost $15, how much will 5 movie tickets cost
Anettt [7]

Answer:

$75

Step-by-step explanation:

15 x 5 = 75

trust me bro :)

7 0
3 years ago
Multiply the polynomials.<br> (4x- + 4x + 6)(7x + 5)
SashulF [63]

\implies {\blue {\boxed {\boxed {\purple {\sf {   \: 28 {x}^{3}  + 48 {x}^{2}  + 62x + 30}}}}}}

\large\mathfrak{{\pmb{\underline{\red{Step-by-step\:explanation}}{\red{:}}}}}

(4 {x}^{2}  +  4x + 6)(7x + 5)

= \: 7x(4 {x}^{2}  + 4x + 6) + 5(4 {x}^{2}  + 4x + 6)

=  \: 28 {x}^{3}  + 28 {x}^{2}  + 42x + 20 {x}^{2}  + 20x + 30

Combining like terms, we have

=  \: 28 {x}^{3}  + (28 {x}^{2}  + 20 {x}^{2} ) + (42x + 20x) + 30

=  \: 28 {x}^{3}  + 48 {x}^{2}  + 62x + 30

\large\mathfrak{{\pmb{\underline{\orange{Mystique35 }}{\orange{❦}}}}}

3 0
3 years ago
In the following arithmetic number pattern: 5,9,13,17... what is the 100th term?
irakobra [83]
Answer:891

Explanation:
1st term+common difference(desired term-1)

5+4(100-1)
9(100-1)
9•99
891
6 0
4 years ago
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