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laiz [17]
3 years ago
8

Please help me with this will reward brainlest

Mathematics
2 answers:
larisa [96]3 years ago
6 0

5.35 + 3.8 + 2 = 11.15 pounds in total

Answer

D. 11.15

Crazy boy [7]3 years ago
5 0

11.15 (D) if you add 5.35 plus 3.8 plus 2 you get 11.15                

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Solve for n.<br><br> 2 n - 3 / 5 = 5<br><br> n =
Finger [1]

Answer: 2 4/5 or 14/5 or 2.5

4 0
3 years ago
Find the quotient of the quantity negative 6 times x to the 2nd power times y to the 8th power plus 12 times x times y to the 3r
olga nikolaevna [1]
[ - 6 * x^2 * y^8 + 12*  x * y^3 - 36 * x * y^2 ] / [6*x*y^2] =

[-6x^2 y^8 ] / [6xy^2] + [12x y^3] / [6xy^2] - [36xy^2] / [6xy^2] =

- xy^6 + 2y - 6

Answer: - xy^6 + 2y - 6

6 0
4 years ago
Read 2 more answers
Suppose that a spherical droplet of liquid evaporates at a rate that is proportional to its surface area: where V = volume (mm3
Alex

Answer:

V = 20.2969 mm^3 @ t = 10

r = 1.692 mm @ t = 10

Step-by-step explanation:

The solution to the first order ordinary differential equation:

\frac{dV}{dt} = -kA

Using Euler's method

\frac{dVi}{dt} = -k *4pi*r^2_{i} = -k *4pi*(\frac {3 V_{i} }{4pi})^(2/3)\\ V_{i+1} = V'_{i} *h + V_{i}    \\

Where initial droplet volume is:

V(0) = \frac{4pi}{3} * r(0)^3 =  \frac{4pi}{3} * 2.5^3 = 65.45 mm^3

Hence, the iterative solution will be as next:

  • i = 1, ti = 0, Vi = 65.45

V'_{i}  = -k *4pi*(\frac{3*65.45}{4pi})^(2/3)  = -6.283\\V_{i+1} = 65.45-6.283*0.25 = 63.88

  • i = 2, ti = 0.5, Vi = 63.88

V'_{i}  = -k *4pi*(\frac{3*63.88}{4pi})^(2/3)  = -6.182\\V_{i+1} = 63.88-6.182*0.25 = 62.33

  • i = 3, ti = 1, Vi = 62.33

V'_{i}  = -k *4pi*(\frac{3*62.33}{4pi})^(2/3)  = -6.082\\V_{i+1} = 62.33-6.082*0.25 = 60.813

We compute the next iterations in MATLAB (see attachment)

Volume @ t = 10 is = 20.2969

The droplet radius at t=10 mins

r(10) = (\frac{3*20.2969}{4pi})^(2/3) = 1.692 mm\\

The average change of droplet radius with time is:

Δr/Δt = \frac{r(10) - r(0)}{10-0} = \frac{1.692 - 2.5}{10} = -0.0808 mm/min

The value of the evaporation rate is close the value of k = 0.08 mm/min

Hence, the results are accurate and consistent!

5 0
3 years ago
The number of sunrises that happen each year is measured in the __
Softa [21]

Answer:

I'm not sure but I think in the hundreds.

Step-by-step explanation:

There are about 365 sunrises a year. So that is in the hundreds.

I have no clue, sorry :(

8 0
3 years ago
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Please help ASAP<br>the answer are within the pic
DerKrebs [107]

Hey Ive taken this assesment. The answer is 55


6 0
3 years ago
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