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Sonbull [250]
3 years ago
12

Plz help me depends on my final grade

Mathematics
2 answers:
Vika [28.1K]3 years ago
7 0
11 miles away from angelicas house
Elina [12.6K]3 years ago
4 0
I think it's 6 miles away
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Need help............
svp [43]

Answer:

i would say C

Step-by-step explanation:

6 0
2 years ago
An insurance company offers its policyholders a number of different premium payment options. For a randomly selected policyholde
kherson [118]

Answer:

Step-by-step explanation:

Given that X is the number of months between successive payments

Cumulative distribution function of X is

F(x) =0, x

a) PMF of x would be

P(x) =0, x

b) P(3 ≤ X ≤ 6) =0.86-0.44=0.42\\ P(4 ≤ X)=1-0.44=0.56\\P(3 < X < 6) =0.6\\P(4 < X) =1-0.48=0.52

4 0
2 years ago
Olivia wrapped a string around a circle and found it was 30 mm long. Approximately, what is the radius of this circle
mafiozo [28]

Answer:7.5

Step-by-step explanation: cause I looked it up lol

8 0
3 years ago
After being rejected for employment, Kim Kelly learns that the Bellevue Credit Company has hired only five women among the last
Georgia [21]

Answer:

The probability that 5 or fewer women are hired, assuming no gender discrimination, is 0.0317; we can use this result to support her charge of gender discrimination.

Step-by-step explanation:

If we are assuming that the women and the men are equally qualified, then the probability for each employee that is hired the probability for it to be a women should be 1/2. Note that the fact that more men that women are hired in a sample might not be disctrimination: for example, if 2 men are hired out of 2 employees, that can happen with probability 1/4, so it is quite common. In order to support her charge for gender discrimination, we need at least a probability less that 0.05 that 5 (or less) women are hired out of 19 employees.

Since each configuration is equally probable, we will count the total amount of possible cases that 5 or less women are hired, and dividide it by the total amount of cases, 2¹⁹.

  • 0 women hired: one possible case: every employee is male
  • 1 women hired: 19 possible cases
  • 2 women hired: {19 \choose 2} = 171 possible cases
  • 3 women hired: {19 \choose 3}  = 969 possible cases
  • 4 women hired: {19 \choose 4} = 3876 possible cases
  • 5 women hired: {19 \choose 5} = 11628 possible cases

Thus, there are a total of 11628+3876+969+171 = 16644 possible cases out of 2¹⁹ ones. All of them with seemingly equal probability. As a consequence, the probability of 5 or less women to be hired out of 19 employees, assuming that the probability to hire 1 is 1/2, is

16644/2¹⁹ = 0.0317 < 0.05

The probability that 5 or fewer women are hired, assuming no gender discrimination, is 0.0317. Since the probability is so low, we can conclude that for the employer, a woman equally qualified as a man is less likely to be hired, therefore, we can support her charge of gender discrimination.

6 0
3 years ago
Help im still lazy lol
jonny [76]

Answer:

t=-105

Step-by-step explanation:

-\frac{1}{15} t =7

What we need to do here is to isolate t.

Let's multiply both sides by -15.

-\frac{1}{15}t  * -15 = 1t

7*-15= -105

t=-105

6 0
3 years ago
Read 2 more answers
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