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2 years ago

I need answers for #3 and #4

Mathematics

1 answer:

NNADVOKAT [17]2 years ago

8 0

Answer:#3- C. E=155

#4- I think it's G‍♀️

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The nearest ten 1202(38)

Advocard [28]

Answer:

1202 is rounded to 1200

38 is rounded to 40

1200(40)= 48,000

7 0

2 years ago

Molly bought two cabbages for 1.80 how many cabbages could she buy with 28.80

Alika [10]

She can buy 16 cabbages .

3 0

3 years ago

adiocarbon dating of blackened grains from the site of ancient Jericho provides a date of 1315 BC ± 13 years for the fall of the

Zigmanuir [339]

Answer:

$\left(\frac{m(t)}{m_{o}} \right)_{min} \approx 0.659$ and $\left(\frac{m(t)}{m_{o}} \right)_{max} \approx 0.661$

Step-by-step explanation:

The equation of the isotope decay is:

$\frac{m(t)}{m_{o}} = e^{-\frac{t}{\tau} }$

14-Carbon has a half-life of 5568 years, the time constant of the isotope is:

$\tau = \frac{5568\,years}{\ln 2}$

$\tau \approx 8032.926\,years$

The decay time is:

$t = 1315\,years + 2007\,years \pm 13\,years$ (There is no a year 0 in chronology).

$t = 3335 \pm 13\,years$

Lastly, the relative amount is estimated by direct substitution:

$\frac{m(t)}{m_{o}} = e^{-\frac{3335\,years}{8032.926\,years} }\cdot e^{\mp\frac{13\,years}{8032.926\,years} }$

$\left(\frac{m(t)}{m_{o}} \right)_{min} = e^{-\frac{3335\,years}{8032.926\,years} }\cdot e^{-\frac{13\,years}{8032.926\,years} }$

$\left(\frac{m(t)}{m_{o}} \right)_{min} \approx 0.659$

$\left(\frac{m(t)}{m_{o}} \right)_{max} = e^{-\frac{3335\,years}{8032.926\,years} }\cdot e^{\frac{13\,years}{8032.926\,years} }$

$\left(\frac{m(t)}{m_{o}} \right)_{max} \approx 0.661$

4 0

2 years ago

Samuel has an auto insurance policy that covers theft up to $15,000, with a $250 deductible. His car is worth $8,000. What will

Yanka [14]

Answer:A

Step-by-step explanation:

If the auto insurance covers theft up to $15,000 and his car value is less than it ($8,000), he is going to pay only $250 deductible. It means that it covers values until $15,000.

5 0

3 years ago

ΔABC is dilated by a scale factor of 0.25 with the origin as the center of dilation, resulting in the image ΔA′B′C′. If A = (-1,

AfilCa [17]

Answer:

c. d = 5

Step-by-step explanation:

The difference in coordinates B and C is (14, 17) -(2, 1) = (12, 16). When the figure is scaled by 0.25, that difference becomes ...

0.25(12, 16) = (3, 4)

The length of a line segment with those coordinate differences is ...

d = √(3² +4²) = √25 = 5 . . . . matches selection c.

3 0

2 years ago