Please help me with this problem.............
1 answer:
Answer:
14
Step-by-step explanation:
Given
- C=5x+4y
- x≤-2
- x≥-4
- y≥1
- y≤6
Here we are asked to find the maximum value of C
C is a sum of factors of x and y
As both the co-efficients of x and y are positive, we have to select the maximum values of both in their given ranges
(if any of their co-efficients was negative, the term whose co-efficient is negative is to be substituted with its least value in its range to get maximum value of C)
Therefore Maximum value of x=-2 and y=6
therefore C
Therefore maximum value of C=14
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Answer:
x = {-5π/4, -3π/4, 3π/4, 5π/4}
Step-by-step explanation:
You know that sec(x) = 1/cos(x), so this is equivalent to ...
cos(x) = -1/√2
The cosine has a magnitude of 1/√2 for an angle of 45°, or π/4 radians. It is negative in the 2nd and 3rd quadrants. Angles in those quadrants that have a reference angle of π/4 are ...
3π/4, 5π/4
We also want angles in the range -2π to 0, so all of the solutions will be ...
sec(x) = -√2 for x = {-5π/4, -3π/4, 3π/4, 5π/4}
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We like to use the x-intercept as the solution when graphing, so we write the given equation as ...
sec(x) +√2 = 0
The graph verifies the above solutions.
