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3 years ago

Please help me with this problem.............

Mathematics

1 answer:

algol [13]3 years ago

7 0

Answer:

Step-by-step explanation:

Given

C=5x+4y
x≤-2

x≥-4

y≥1
y≤6

Here we are asked to find the maximum value of C

C is a sum of factors of x and y

As both the co-efficients of x and y are positive, we have to select the maximum values of both in their given ranges

(if any of their co-efficients was negative, the term whose co-efficient is negative is to be substituted with its least value in its range to get maximum value of C)

Therefore Maximum value of x=-2 and y=6

therefore C

$= 5\times -2 + 4\times 6\\= -10 + 24\\= 14$

Therefore maximum value of C=14

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pantera1 [17]

Answer:

C. the figure moves left and down

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

An elevator has a placard stating that the maximum capacity is 1580 lb-10 passengers. So, 10 adult male passengers can have a m

disa [49]

Answer:

a) 0.5714 = 57.14% probability that it is overloaded because they have a mean weight greater than 158 lb

b) No, because the probability of being overloaded is considerably high(57.14%). Ideally, it should be under 5%, which would be considered an unusual event.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Assume that weights of males are normally distributed with a mean of 160 lb and a standard deviation of 35 lb.

This means that $\mu = 160, \sigma = 35$

Sample of 10:

This means that $n = 10, s = \frac{35}{\sqrt{10}} = 11.07$

a) Find the probability that it is overloaded because they have a mean weight greater than 158 lb.

This is 1 subtracted by the pvalue of Z when X = 158. So

$Z = \frac{X - \mu}{\sigma}$

By the Central Limit Theorem

$Z = \frac{X - \mu}{s}$

$Z = \frac{158 - 160}{11.07}$

$Z = -0.18$

$Z = -0.18$ has a pvalue of 0.4286

1 - 0.4286 = 0.5714

0.5714 = 57.14% probability that it is overloaded because they have a mean weight greater than 158 lb.

b.) Does this elevator appear to be safe?

No, because the probability of being overloaded is considerably high(57.14%). Ideally, it should be under 5%, which would be considered an unusual event.

8 0

3 years ago

3∣a−b∣ if a=−9 and b=3

yKpoI14uk [10]

Answer:

36 because the absolute value of -9-3 is 12, and then 12 times 3 is 36

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3 years ago

Convert each number from scientific notation to standard notation. (A) 1.18 x 10to the power of 3

Natali5045456 [20]

(A) 1.18*10^3

When you multiply by 10^3, that means you're moving the decimal 3 places to the right.
1.18 becomes <em>1,180</em>.

(B) 6.701*10^-2

When you multiply by a negative exponent, it moves the decimal to the left. 10^-2 moves the decimal 2 places to the left.
6.701 becomes <em>0.0671</em>

6 0

3 years ago

Suppose we want to choose letters, without replacement, from distinct letters.

Juli2301 [7.4K]

The number of ways when the choice is not relevant is 1716

<h3>How to determine the number of ways?</h3>

The number of letters are:

Letter, n = 13

The letter to choose are:

r = 6

<u>Relevant choice</u>

When the choice is relevant, we have:

$Ways = ^nP_r$

This gives

$Ways = ^{13}P_6$

Evaluate

Ways = 241235520

Hence, the number of ways when the choice is relevant is 1235520

<u>Not relevant choice</u>

When the choice is not relevant, we have:

$Ways = ^nC_r$

This gives

$Ways = ^{13}C_6$

Evaluate

Ways = 1716

Hence, the number of ways when the choice is not relevant is 1716