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There are ways of picking 2 of the 10 available positions for a 0. 8 positions remain.
There are ways of picking 3 of the 8 available positions for a 1. 5 positions remain, but we're filling all of them with 2s, and there's
way of doing that.
So we have
The last expression has a more compact form in terms of the so-called multinomial coefficient,
Answer:
Step-by-step explanation:
The y-intercept is where x is 0 (0,y)
The x-intercept is where y is 0 (x,0)
Insert 0 as the value for x to find the corresponding y value:
Simplify multiplication:
Isolate the variable. Divide both sides by 4:
Make the variable positive. Multiply both sides by -1:
The y-intercept is at .
Insert 0 as the value for y to determine the value of x:
Simplify multiplication:
Isolate x. Divide both sides by 5:
Multiply both sides by -1:
The x-intercept is at .
:Done