Answer:
Displacement will be 11 revolution and 1.02π radian
Step-by-step explanation:
We have given that initial angular position = 0.45 radian
Angular speed 
Time is given as t = 8.8 sec
So angular displacement in 8.8 sec

As he has already covered 0.45 radian
So total angular displacement = 0.45 + 71.8432 = 72.2932 radian
We know that 1 revolution = 2π = 2×3.14 = 6.28 radian
So 11 revolution = 11×6.28 = 69.08 radian
Left dispalcement = 72.2932 - 69.08 = 3.2132 radian = 1.02π radian
The set contains only vowels
Sin(12) ≈ 0.208
cos(x) = 0.208
cos(x) = sin(12)
cos(78) = sin(12)
cos(12) ≈ 0.978
cos(68) ≈ 0.375
cos(102) ≈ -0.208
cos(78) ≈ 0.208
The answer is D.
C=5/9(F-32) 5/9 =1.8 32-32= 0* 1.8 = 0 32F= 0Celsius 40-32=8* 14.4 40F= 14.4 CTemperature between 0-14 degrees Celsius