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3 years ago

What’s the correct answer for this?

Mathematics

1 answer:

Citrus2011 [14]3 years ago

7 0

Answer:

the distance of the rope between boat and dock is 30

Step-by-step explanation:

to get the distance between the rope and the dock we use tan 40 because we have the opposite as 25.17ft

tan 40 = opposite/adjacent

0.839 = 25.17/a

cross multiply

0.839a= 25.17

a = 25.17/0.839 = 30 ft

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Please help. I will give brainliest!

Andrej [43]

Answer:

Step-by-step explanation:

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7 0

3 years ago

Find the x value for the point that splits segment AB in half if point A is located at (4, 3) and point B is located at (−2, 6).

erastova [34]

Midpoint = (x1+x2)/2 and (y1+y2)/2 = so just solving for
x gives (4+(-2))/2 = 1

not asked for but the y value is (3+6)/2 = 9/2 = 4.5 so the ordered pair is (1, 4.5)

3 0

3 years ago

Read 2 more answers

How to solve 9(n+3)=7n-3)

Licemer1 [7]

$9(n+3)=7n-3$

$9n+12=7n-3$

$2n = -15$

$n =- \frac{15}{2}$

8 0

3 years ago

Read 2 more answers

25 points

lbvjy [14]

Answer:

unit_4_study_guide_solutions.pdf

Step-by-step explanation:

This link is a study guide, and on the LAST PAGE it has the answer to your question!

4 0

3 years ago

Drag each tile to the correct box.

Natasha_Volkova [10]

Answer:

1) Function h

interval [3, 5]

rate of change 6

2) Function f

interval [3, 6]

rate of change 8.33

3) Function g

interval [2, 3]

rate of change 9.6

Step-by-step explanation:

we know that

To find the average rate of change, we divide the change in the output value by the change in the input value

the average rate of change is equal to

$\frac{f(b)-f(a)}{b-a}$

step 1

Find the average rate of change of function h(x) over interval [3,5]

Looking at the third picture (table)

$f(a)=h(3)=4$

$f(b)=h(5)=16$

$a=3$

$b=5$

Substitute

$\frac{16-4}{5-3}=6$

step 2

Find the average rate of change of function f(x) over interval [3,6]

Looking at the graph

$f(a)=f(3)=10$

$f(b)=f(6)=35$

$a=3$

$b=6$

Substitute

$\frac{35-10}{6-3}=8.33$

step 3

Find the average rate of change of function g(x) over interval [2,3]

we have

$g(x)=\frac{1}{5}(4)^x$

$f(a)=g(2)=\frac{1}{5}(4)^2=\frac{16}{5}$

$f(b)=g(3)=\frac{1}{5}(4)^3=\frac{64}{5}$

$a=2$

$b=3$

Substitute

$\frac{\frac{64}{5}-\frac{16}{5}}{3-2}=9.6$

therefore

In order from least to greatest according to their average rates of change over those intervals

1) Function h

interval [3, 5]

rate of change 6

2) Function f

interval [3, 6]

rate of change 8.33

3) Function g

interval [2, 3]

rate of change 9.6

7 0

3 years ago