Answer: The required scale factor of the dilation is 4.
Step-by-step explanation: Given that the parallelogram FGHJ was dilated and translated to form similar parallelogram F'G'H'J'.
We are to find the scale factor of the dilation.
From the graph, we note that
JH = 2 units and J'H' = 8 units.
We know that

Therefore, the scale factor of the given dilation is

Thus, the required scale factor of the dilation is 4.
Convert the timing into hours only:
11:15 = 11.25h
9:45 = 9.75h
11:45 = 11.75h
7:45 = 7.75h
10:45 = 10.75h
To find the average, we need to find the middle of these timing:
11.25 + 9.75 + 11.75 + 7.75 + 10.75 = 51.25
51.25 ÷ 5 = 10.25h = 10:15 am
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Answer: The average time it docks is 10:15 am.
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Answer:
I could do 1 and 3
1) 2x-3y=-2 ....1
-
2x+y=14......2
=-4y=-16
y=4
<u>Substitute</u><u> </u><u>(</u><u>y</u><u>=</u><u>4</u><u>)</u><u> </u><u>into</u><u> </u><u>equation</u><u> </u><u>1</u>
2x-3 (4)=-2
2x-12=-2
2x=-2+12
2x=10
×=5
3) 5x+5y=20....1
-
-3x+5y=4......2
=8x=16
x=2
<u>S</u><u>ubstitute</u><u> </u><u>(</u><u>x</u><u>=</u><u>2</u><u>)</u><u> </u><u>into</u><u> </u><u>equation</u><u> </u><u>1</u>
<u>5</u><u> </u><u>(</u><u>2</u><u>)</u><u>+</u><u>5y</u><u>=</u><u>20</u>
<u>10</u><u>+</u><u>5y</u><u>=</u><u>20</u>
<u>5y</u><u>=</u><u>20-10</u>
<u>5y</u><u>=</u><u>10</u>
<u>y</u><u>=</u><u>2</u>