4 cos² x - 3 = 0
4 cos² x = 3
cos² x = 3/4
cos x = ±(√3)/2
Fixing the squared cosine doesn't discriminate among quadrants. There's one in every quadrant
cos x = ± cos(π/6)
Let's do plus first. In general, cos x = cos a has solutions x = ±a + 2πk integer k
cos x = cos(π/6)
x = ±π/6 + 2πk
Minus next.
cos x = -cos(π/6)
cos x = cos(π - π/6)
cos x = cos(5π/6)
x = ±5π/6 + 2πk
We'll write all our solutions as
x = { -5π/6, -π/6, π/6, 5π/6 } + 2πk integer k
Answer:
5
Step-by-step explanation:
The degree is just the number with the highest power. In this case, it is 3^5. Therefore, 5 is the degree.
If this helps please mark as brainliest
Your question seems a bit incomplete, but for starters you can write

Expanding where necessary, recalling that

, you have

and you can stop there, or continue to rewrite in terms of the reciprocal functions,

Now, since

, the final form could also take

or
To add a negative and a positive I usually just subtract them so ex: -5+4=-1
and to subtract them I add the numbers together so -5-4=-9 so its basically the opposite