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Aleonysh [2.5K]
3 years ago
13

Students receive 25% off the regular ticket prices at schitterbahn. if the discounted ticket is $44.25, write an equation that c

ould be used to find the regular price, r. (Do not solve)
Mathematics
1 answer:
Natasha2012 [34]3 years ago
4 0

Answer:

(44.25/75)*100 or (44.25/3)*4

Step-by-step explanation:

Divide by the price of $44.25 by 75 (100% - 25%) and mulitily by 100

or $44.25 by 3 and multyply by 4. (25% is a quarter 1/4, so you need 4/4)

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Your averages and values are the following:
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Answer: You need a grade of 78 on the final exam to earn a final grade average of at least 87 in each grading system.

Step-by-step explanation:

(85 + 90 + 95 + x)÷ 4 =87

Simplify:

(270 + x) ÷ 4 = 87

Rearrange:

(x + 270) ÷ 4 = 87

Multiply terms to Reduce:

4((x + 270) ÷ 4) = 4 * 87

Cancel Multiplied terms in Denominator:

x + 270 = 4 * 87

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2 years ago
The number of major earthquakes in a year is approximately normally distributed with a mean of 20.8 and a standard deviation of
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Answer:

a) 51.60% probability that in a given year there will be less than 21 earthquakes.

b) 49.35% probability that in a given year there will be between 18 and 23 earthquakes.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 20.8, \sigma = 4.5

a) Find the probability that in a given year there will be less than 21 earthquakes.

This is the pvalue of Z when X = 21. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{21 - 20.8}{4.5}

Z = 0.04

Z = 0.04 has a pvalue of 0.5160.

So there is a 51.60% probability that in a given year there will be less than 21 earthquakes.

b) Find the probability that in a given year there will be between 18 and 23 earthquakes.

This is the pvalue of Z when X = 23 subtracted by the pvalue of Z when X = 18. So:

X = 23

Z = \frac{X - \mu}{\sigma}

Z = \frac{23 - 20.8}{4.5}

Z = 0.71

Z = 0.71 has a pvalue of 0.7611

X = 18

Z = \frac{X - \mu}{\sigma}

Z = \frac{18 - 20.8}{4.5}

Z = -0.62

Z = -0.62 has a pvalue of 0.2676

So there is a 0.7611 - 0.2676 = 0.4935 = 49.35% probability that in a given year there will be between 18 and 23 earthquakes.

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Answer:

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Step-by-step explanation:

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